Limits of 1/x Explained: A Calculus Question

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This may be a very basic question for this forum. I have just started to Learn Calculus. Please. help me with my question -
Suppose I need to find the Limit of 1/x where x tends to 0 from positive side.
I know from the graph of 1/x that answer is +Infinity.
But if I apply Squeeze theorem to it and the greater function is 1 and smaller function is 1/(1+x).
1/(x+1) < 1/x < 1 : where x is always positive and tends to 0.
The limits of these rightmost and leftmost functions at 0+ is 1. So as per squeeze th. the middle function is 1.

Why it is different from the actual answer? Am I doing something wrong?
 
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Yes. You have erroneously stated that 1/x < 1 for small positive x
 
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oh...such a bad mistake...
thanks David for replying and pointing it out...
 
no problem. don't let it discourage you!
 
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