Limits with Trigonometric Functions and Polynomials

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SUMMARY

The limit of the expression \(\lim_{x\rightarrow0}\frac{2\cos^{2}(x)-\cos(x)-3}{x^{2}}\) was evaluated in the discussion. The numerator was factored to \((2\cos(x)-3)(\cos(x)+1)\), leading to the conclusion that the limit approaches \(-\infty\) as \(x\) approaches 0. This indicates that the function diverges negatively at this point.

PREREQUISITES
  • Understanding of trigonometric functions, specifically cosine.
  • Familiarity with limits in calculus.
  • Ability to factor algebraic expressions.
  • Knowledge of L'Hôpital's Rule for evaluating indeterminate forms.
NEXT STEPS
  • Study the application of L'Hôpital's Rule for limits involving trigonometric functions.
  • Explore the behavior of \(\cos(x)\) near \(x = 0\) for deeper insights into limits.
  • Practice solving limits that result in indeterminate forms.
  • Investigate the implications of limits approaching infinity in calculus.
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Students and educators in calculus, particularly those focusing on limits and trigonometric functions, as well as anyone preparing for advanced mathematics courses.

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Homework Statement



solve the limit:

[tex]\lim_{x\rightarrow0}\frac{2cos^{2}(x)-cos(x)-3}{x^{2}}[/tex]


The Attempt at a Solution



Ok so i factored out the numerator, but i don't know where to go from there any help please.

[tex]\lim_{x\rightarrow0}\frac{2cos^{2}(x)-cos(x)-3}{x^{2}}=\lim_{x\rightarrow0}=\frac{(2cos(x)-3)(cos(x)+1)}{x^{2}}[/tex]
 
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Alright never mind i got limit as x approaches 0 to equal -∞.
 

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