LimSup of a Sequence: Existence & Unbounded Cases

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Homework Help Overview

The discussion revolves around the concept of the limit superior (lim sup) of a sequence in real numbers, particularly focusing on its existence and the implications when the sequence is unbounded. Participants are exploring the definition and properties of lim sup, as well as the behavior of the associated sequence of supremums.

Discussion Character

  • Conceptual clarification, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster defines lim sup and questions its existence, particularly in unbounded cases. They seek clarity on what details are expected in their explanation. Other participants inquire about the nature of the sequence of supremums, questioning whether it is always decreasing and discussing the implications of boundedness.

Discussion Status

The discussion is active, with participants raising questions about the properties of the sequence of supremums and the conditions under which the limit exists. There is no explicit consensus yet, but various interpretations and considerations are being explored.

Contextual Notes

Participants are navigating the requirements of a homework question that demands a detailed explanation, indicating that the expectations may be high for clarity and depth in their responses.

C.E
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1. Let a_n be a sequence in R. Define \limsup_{n \to \infty} a_n. Explain why it exists including the cases when the sequence is unbounded.

3. I did the following, is it ok?

definition:

\limsup_{n \to \infty} a_n=\lim_{n \to \infty} sup_{k \geq n}a_k.

Is this right, I seem to have lost this part of my notes!

I know that when it is not bounded (above) the limsup is infinite. What I am really having

trouble with is explaining why it exists. What do you think they want me to say? (By the

way this question was worth 10 marks so they want a lot of detail).
 
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Let v_n=sup_{k \geq n}a_k

What kind of sequence is v_n? increasing, decreasing, bounded,...
 
Is v_n always a decreasing sequence? It may be bounded or it may not be. If it is bounded then by the completeness axiom its limit must exist, but what if it is not bounded?
 
Last edited:
C.E said:
Is v_n always a decreasing sequence? It may be bounded or it may not be. If it is bounded then by the completeness axiom its limit must exist, but what if it is not bounded?

If it's monotonically decreasing but unbounded, then for every positive B, there is an N such that

v_n \leq -B for all n \geq N

in which case by definition we write

\lim_{n \rightarrow \infty} v_n = -\infty
 
Is it increasing then? If so why?
 

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