Limsupremum calculation horrible difficulty

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
1 reply · 1K views
betty2301
Messages
21
Reaction score
0

Homework Statement


Calculate the radius of convergence of [itex]\sum_{n=0}^\infty a_{n}z^{2n}[/itex]
let [itex]\sum_{n=0}^\infty a_{n}z^{n}[/itex]with radius R

Homework Equations


[itex]\limsup|a_n|^{\frac{1}{n}}=\limsup |\frac{a_{n+1}}{a_n}|[/itex]

The Attempt at a Solution


[tex]\limsup|a_n|^{\frac{1}{n}}=\lim_{k\to\infty}|a_{2k}|^{\frac{1}{2k}}[/tex]
then how to write the "ratio"....
the latex is killin me please help....
 
Last edited:
Physics news on Phys.org
You could use the limsup formula, but it's easier to think about what the radius of convergence means. Basically you're given that the original series converges for |z| < R and diverges for |z| > R, so what happens when you square z?