Lin Alg - Basis of the Space of Solutions of a Linear System

Click For Summary

Homework Help Overview

The discussion revolves around the concept of finding a basis for the space of solutions of a system of linear equations, specifically focusing on homogeneous systems. Participants are examining the validity of solutions provided in a textbook and questioning the relationship between the basis and the solutions to the equations.

Discussion Character

  • Conceptual clarification, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are exploring whether each element in a basis for the space of solutions should be a solution to the original system of equations. There are discussions about the implications of the system being homogeneous versus non-homogeneous. Some participants are questioning the correctness of the textbook's answers and discussing specific examples from the problems presented.

Discussion Status

The conversation is ongoing, with participants providing insights and questioning the textbook's solutions. There is a recognition of potential discrepancies in the book's answers, but no consensus has been reached regarding the correctness of the solutions or the interpretation of the problems.

Contextual Notes

Participants mention specific problems from the textbook, noting that some provided bases do not satisfy the original equations. There is also a mention of a lack of examples in the textbook that could clarify the concepts being discussed.

mattmns
Messages
1,129
Reaction score
5
Just a quick question. If I have a system of linear equations, and I find a basis for the space of solutions, then each element in the basis should be a solution to the system right? Thanks!
 
Physics news on Phys.org
What do you think?
 
I think yes, but if so, then my book has a wrong answer.
 
Well, you should be right. Maybe it means that the system of equations could be nonhomogenous and the "space of solutions" they are talking about is only for the related homogenous system. Or maybe they are just wrong.
 
I am dealing with homogenous systems, sorry for not specifying that earlier. The book has 4 problems like this, 3 of which have a bases, 2 of which are not solutions to the entire solution. Here is the actual problem and answer from the book.

----------------

What is the dimension of the space of solutions of the following system of linear equations? In each case, find a basis for the space of solutions.
(a)
2x + y - z = 0
2x + y + z = 0
-----
The dimension is 1, and the books basis is (1,-1,0)
-----
But this element is not a solution to the above system. In my opinion, the basis should be (1, -2, 0). [fixed typo]

then for part (c)
[itex]4x + 7y - \pi z = 0[/itex]
[itex]2x - y + z = 0[/itex]
------
The book then says that the dimension is 1, which is what I got, but it says that the basis is [tex]( \frac{\pi - 3}{10} , \frac{ \pi + 2}{5} , 1 )[/tex]

But this basis is not a solution to both equations (it does not work for the first equation), and therefore not a solution to the system.
-------------

And, for part (b) the elements in the book's basis is a solution to the system, and for part (d) there is no basis.

Am I missing what the book is getting at (there are no examples of a similar problem), or do you think the book is just wrong? Thanks.
 
Last edited:
Well, for a the correct answer is (1, -2, 0). For c the dimension is actually 2.
 
0rthodontist said:
Well, for a the correct answer is (1, -2, 0). For c the dimension is actually 2.
You are right about a, that was my typo :smile:

But for c how are you getting the dimension as 2?
 
Ah, my mistake, never mind.

I don't know why your book is having so many errors. Maybe you are looking at the wrong solutions?
 
lol, no they are the right "solutions."

Thanks for the help!
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
3K
Replies
15
Views
3K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 18 ·
Replies
18
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
34
Views
4K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
4
Views
2K
  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K