Line Integral Fundamental Theorem

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SUMMARY

The discussion centers on applying the Fundamental Theorem of Line Integrals using the scalar potential function Phi = xy + y² + C to evaluate a line integral from the point (0,2) to (-2,0). The calculation involves the gradient of the function and the evaluation of the potential function at the endpoints, resulting in a difference of 4. A participant points out an error regarding a missing minus sign in the calculations, indicating that the initial answer may have been incorrect. The final evaluation confirms the application of the theorem, ensuring consistency with previous results.

PREREQUISITES
  • Understanding of the Fundamental Theorem of Line Integrals
  • Knowledge of scalar potential functions in vector calculus
  • Familiarity with gradient calculations
  • Ability to evaluate line integrals in two-dimensional space
NEXT STEPS
  • Review the Fundamental Theorem of Line Integrals in detail
  • Practice calculating gradients of scalar functions
  • Explore examples of line integrals in vector fields
  • Investigate common errors in line integral evaluations
USEFUL FOR

Students and educators in calculus, particularly those focusing on vector calculus and line integrals, as well as anyone looking to solidify their understanding of the Fundamental Theorem of Line Integrals.

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Homework Statement


Use Your Phi(from part 1) and the fundamental theorem of line integrals to evaluate the same line integral. (should get the same answer!)



The Attempt at a Solution



Phi from part 1: Phi = xy+ y^2 +C

The line from before go from (0,2) to (-2,0)

r(a) = (0,2) r(b)= (-2,0)

Gradient F * Dr = f(r(b))-f(r(a))
= f(-2,0)-f(0,2)
= (-2*0+0^2)- (0*2+2^2)=4

I'm not sure if this is right, it's not the same answer I got before, I'm not sure what one I got wrong.
 
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For one, you're clearly missing a minus sign.
 
snipez90 said:
For one, you're clearly missing a minus sign.

Other than that is it good?
 

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