Line Integral of a Vector Field over a Half Sphere using Stoke's Theorem

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SUMMARY

The discussion centers on the application of Stoke's Theorem to compute the line integral of the vector field F = (2y i + 3x j + z^2 k) over the upper half of the sphere defined by x² + y² + z² = 9. The initial calculation using the line integral yielded a result of 9π, while the application of Stoke's Theorem provided a result of 36π. The discrepancy was resolved by correctly considering the normal vector after computing the curl, leading to a consistent result of 9π for both methods.

PREREQUISITES
  • Understanding of Stoke's Theorem
  • Knowledge of vector fields and line integrals
  • Familiarity with surface integrals
  • Ability to compute curl of a vector field
NEXT STEPS
  • Review the application of Stoke's Theorem in vector calculus
  • Practice computing curl for various vector fields
  • Learn about parametrization of surfaces in three dimensions
  • Explore the relationship between line integrals and surface integrals
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Students and educators in mathematics, particularly those studying vector calculus, as well as anyone involved in solving complex integrals using Stoke's Theorem.

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Homework Statement



F = ( 2y i + 3x J + z2 k where S is the upper half of the sphere x2 + y2 + z2 = 9 and C is its boundary.

Homework Equations





The Attempt at a Solution



I used Stoke's Theorem and found the solution to be 36 pi, but when I use line integral to verify, using substition:

r(t) = 3cost i + 3sin t j

F(r(t))r'(t) = 9 (-2sin2t + 3cos2t)

\int^{2 pi}_{0} 9 (-2sin2t + 3cos2t)

= 9 (1/2 + 5/2 cos(2t))/^{2 pi}_{0}

= 9 pi which doesn't agree with 36 pi.

I wonder if I did my substitution wrong. Should I do anything with z or the k component?

Thank you!
 
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The math looked right to me, so I did the curl side and parametrized the surface. I found the answer to be 9 \pi both ways. Check your curl, and make sure you are actually dealing with the curl vector dotted with the normal vector to the surface.
 
Thank you!

Yes I forgot to consider the normal after computing the curl. So I get to surface integral of 1 which translates into double integral of 1 over the region enclosed by S and since x and y form a circle the region is the area of a circle which is 9 pi.
 

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