Linear 2-port network representation

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about the existence of implicit representation for a linear 2-port network
Hi,

in the context of linear two-ports networks my (italian) textbook says that if its internal structure consists of passive one-port components with no independent current/voltage generators then the following (implicit) linear equations based representation always exist:

##\left[A\right] V + \left[B\right] I = 0## where ##V## is the column vector of port voltages and ##I## that of port currents

Now, if we take in account just only resistors as passive one-port components than the reason behind is clear: just close the 2-port network with 2 resistor and apply the Tellegen theorem to the overall circuit. All voltages and currents have to be null so the complete set of linear equations have to be linear independent, thus by elimination the two linear equations representing the 2-port network are independent themselves.

On the other hand, what if we include (voltage and/or current) controlled generators as one-port component inside the internal structure of the 2-port network ? Starting from the complete set of linear equations can we always obtain that linear representation by elimination ?
 

anorlunda

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If I understand right, you are describing a linear network with nonlinear boundary conditions. The controlled generators make the nonlinear boundary conditions.

Do you realize that is a description of the power grid? You could model the entire European power grid as you describe. A linear network with nonlinear boundary conditions. Because of the nonlinearities, solutions must be iterative.
 
If I understand right, you are describing a linear network with nonlinear boundary conditions. The controlled generators make the nonlinear boundary conditions.
As far as I can tell maybe my point is not clear...

Controlled generators we're talking about are inside the 2-port network (inside the 'black-box' accessible from 2 ports). Just as an example consider a 2-port accessible 'black-box' with a (current) controlled voltage generator inside. Its value depends linearly on the current flowing through another component inside the network itself.
 
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anorlunda

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If the controlled generator responds with anything other than constant impedance (for example constant power), it becomes a nonlinear device. In general, you can not eliminate them with linear equations.

You can make a piecewise linear representation and solve that, but the solution is valid only at one operating point.

If you have trouble visualizing that, just imagine the network having no components other than the controlled generator. Would that fit your linear equations?

The general way to handle those problems is to treat the generators as external components, not part of the network. That leads you to linear network with nonlinear boundary conditions as I described before.
 
If the controlled generator responds with anything other than constant impedance (for example constant power), it becomes a nonlinear device. In general, you can not eliminate them with linear equations.
Consider the following two-port network in which the controlled generator voltage ##V_g## is equal to ##K*I_3## (##I_3## is the current through ##R_3##)
schema.JPG


Here the 2-port network has a simple external representation (a 2 equations homogeneous linear system), don't you ?

##\begin{bmatrix} V_a\\V_b\end{bmatrix} + \left[B\right]\begin{bmatrix} I_a\\I_b\end{bmatrix} = 0##
 

anorlunda

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I see two networks. IA is not dependent on anything on the B side. Solve for IA first, then get VG, then IB. The equations are not simultaneous. Giving the B side an external dependency on A, does not pull A into a set of simultaneous equations unless A depends on B.
 
Sorry, but I'm not able to catch your point....

Just to rephrase the original question: consider the following schema - a box internally made of linear two-pole elements with no independent current/voltage generators, externally accessible from 2 ports each one closed on a two-pole element.
Capture.JPG

Does the following linear equations system representation always exist for it ?

##\left[A\right] V + \left[B\right] I = 0##; ##V=\begin{bmatrix} V_a\\V_b\end{bmatrix}## and ##I=\begin{bmatrix} I_a\\I_b\end{bmatrix}##
 

kimbyd

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Summary: about the existence of implicit representation for a linear 2-port network

Hi,

in the context of linear two-ports networks my (italian) textbook says that if its internal structure consists of passive one-port components with no independent current/voltage generators then the following (implicit) linear equations based representation always exist:

##\left[A\right] V + \left[B\right] I = 0## where ##V## is the column vector of port voltages and ##I## that of port currents

Now, if we take in account just only resistors as passive one-port components than the reason behind is clear: just close the 2-port network with 2 resistor and apply the Tellegen theorem to the overall circuit. All voltages and currents have to be null so the complete set of linear equations have to be linear independent, thus by elimination the two linear equations representing the 2-port network are independent themselves.

On the other hand, what if we include (voltage and/or current) controlled generators as one-port component inside the internal structure of the 2-port network ? Starting from the complete set of linear equations can we always obtain that linear representation by elimination ?
I believe this question is equivalent to the question, "Can you diagonalize a matrix?"

And I'm pretty sure the answer to that will always be "yes" for a properly-defined network. In particular, if the matrix is symmetric it is always diagonalizable.
 

marcusl

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I think that the matrix must be invertible to be diagonalizable.
 
I believe this question is equivalent to the question, "Can you diagonalize a matrix?"

And I'm pretty sure the answer to that will always be "yes" for a properly-defined network. In particular, if the matrix is symmetric it is always diagonalizable.
I tried to reason as follows. Consider the complete circuit obtained closing each 'box' port with a two-pole linear element. Assume the box inside consists of connected two-pole linear elements with no independent voltage/current generators.

Starting from it, write down KCL, KVL and two-pole linear costitutive equations (including controlled generators if any inside) getting an homogeneous linear system having the number of linear equations the same as the number of unknowns (square system resolution matrix)

Take for instance the network in post #7 having a resolving matrix with 14 rows and 14 unknowns (14x14)
[tex]
\begin{pmatrix}
* & * & * & * & * & * & * & * & * & * & * & * & * & * & \\
* & * & * & * & * & * & * & * & * & * & * & * & * & * & \\
* & * & * & * & * & * & * & * & * & * & * & * & * & * & \\
* & * & * & * & * & * & * & * & * & * & * & * & * & * & \\
\vdots \\
0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & a & b & 0 & 0 \\
0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & c & d \\
\end{pmatrix} \begin{pmatrix}
* \\
* \\
* \\
* \\
\vdots \\
V_{a} \\
I_{a} \\
V_{b} \\
I_{b} \\
\end{pmatrix}
[/tex]
By means of Gauss elimination we can transform it into raw echelon form up to the last 4 raws (basically eliminating 14-4=10 voltage/current unknowns 'inside' the box). At that point we find ourselves with a set of linear equations involving just only the port voltage/current unknowns. From those we can obtain up to to 4 independent linear equations (last 2 are independent each other for sure).

This way we can conclude '2 linear equation representation" always exist with the given conditions even if we cannot assume, in general, they are independent though.....
 

The Electrician

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cianfa72, you might find it useful to study this page: https://en.wikipedia.org/wiki/Two-port_network

I think the representation you're looking for: "[A]V+I=0 where V is the column vector of port voltages and I that of port currents "

is called "ABCD" parameters on that page.

Often, a network in a black box can be characterized by any of the 6 parameter sets, and any particular one can be transformed to any other one using the table "Interrelation of parameters" at the bottom of the Wikipedia page.

It is possible to have a black box with a network of two terminal elements inside that cannot be represented by every one of the 6 parameter sets on the Wikipedia page. For example, the network consisting of a single resistor from the a (input) port to the b (output) port can be represented with admittance parameters, but not with impedance parameters.

If there is no coupling either in the forward or the reverse direction, which is lacking in your network of post #7, there probably won't be a representation in ABCD parameters.

The network in post #5 does have coupling from the input port to the output port (but not in the reverse direction), so it does have an ABCD parameter representation.
 
cianfa72, you might find it useful to study this page: https://en.wikipedia.org/wiki/Two-port_network

I think the representation you're looking for: "[A]V+I=0 where V is the column vector of port voltages and I that of port currents "

is called "ABCD" parameters on that page.
from wikipedia link [A]V+I=0 -> I = - [A]V should be actually the y-parameters model.

I think the main point is that, starting from let me say the 'implicit' representation ##\left[A\right] V + \left[B\right] I = 0## we assume always exist (see my previous post #10), the 6 models result from a different selection of the 2 independent port variable (combination without repetition of 2 element taken in 4 is actually 6)

If there is no coupling either in the forward or the reverse direction, which is lacking in your network of post #7, there probably won't be a representation in ABCD parameters.
ok that's right.
 

The Electrician

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When I "copied and pasted" from post #1, part of what I copied wasn't bold, and in the process of fixing that, something got lost. I should have had:

XXXXX.png


This gives ABCD parameters.

I think it's easier to just use the nodal method of analysis to get the two-port Y parameters in a couple of steps.
The admittance matrix for your network in post #5 can be written by inspection like this:

There are 4 nodes if a non-essential node is placed between the controlled source and R4.

Then all the (internal) nodes except the two port nodes are eliminated using the Schur complement technique: https://en.wikipedia.org/wiki/Schur_complement (as described under the heading "Application to solving linear equations").

Do Schur.png
 

The Electrician

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Can you use the procedure you describe in post #10 to find two equations for what is probably the simplest case with no coupling:

BlackBox1.png
 

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