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## Homework Statement

A 30 kg wheel has a center of mass 0.1 m left from the center of the wheel and radius of gyration KG = 0.15 m. Find the angular acceleration if the wheel is originally at rest. The radius of the wheel is 0.25m.

## Homework Equations

I=mk^2

T=f*d

M=I*a

Fn acting bottom in Y direction = m*g

## The Attempt at a Solution

I=mk^2=(30)*(15^2)=0.675kg*m^2

Fx=0

Fn=(30*9.81)=294.3N

Sum of force in Y: Fn-mg=mass*angular acceleration*radius to center

294.3-294.3=30*a*0.1

Moment about center =ig*a*radius to center of mass

(294.3*.1)=(.675)*a*.1

... lost from here?

Apparently answer is 10.3 rad/s^2

Help please! Been working on this for hours