Linear algebra - basis of subspace

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To find a basis of the subspace in R4 consisting of vectors perpendicular to (1, 0, 5, 2) and (0, 1, 5, 5), one must ensure the vectors are linearly independent and span the space. The dot product of any vector u = (u1, u2, u3, u4) with the given vectors must equal zero, resulting in two equations with four unknowns. This approach leads to a system of equations that can be solved to identify the basis. The Gram-Schmidt process is mentioned as a potential method for orthogonalization, although it may not be necessary for this specific problem. Ultimately, the key is to derive the equations from the dot products to determine the required basis.
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Homework Statement



Find a basis of the subspace of R4 that consists of all vectors perpendicular to both

(1
0
5
2)

and

(0
1
5
5)

^ those are vectors.


Homework Equations





The Attempt at a Solution



I understand that a basis needs to be linearly independent and that it needs to span the vector space, but I am thrown off by the fact that the basis needs to consist of vectors perpendicular to those vectors above.
 
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do you know about orthogonal projections? or perhaps the gram-schmidt process? seems like the perfect time to use it. don't know if wikipedia links are allowed to be posted here, but here is a link to gram schmidt in case you haven't read about it. the process itself might seem tedious but is very simple.

http://en.wikipedia.org/wiki/Gram–Schmidt_process

hope this helps.

cj.
 
Another approach is to Let u = (u1, u2, u3, u4) be a vector in R4.

Since u is perpendicular to both of your given vectors, the dot product of u with each of the given vectors should be 0. That will give you two equations in four unknowns. These equations can be used to find a basis for your subspace.
 
Last edited:
thanks! i got it :)
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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