Linear algebra: Determine if this set is a vector space.

Click For Summary

Homework Help Overview

The discussion revolves around determining whether a specific set of polynomials, defined with standard scalar multiplication and a non-standard addition operation (polynomial multiplication), constitutes a vector space. Participants are exploring the implications of this warped addition on the properties required for a vector space.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants are examining the associativity of the warped addition and questioning how scalar multiplication interacts with this operation. Some are attempting to provide examples to illustrate their points, while others are seeking clarification on the underlying field of the polynomials.

Discussion Status

The conversation includes various attempts to analyze the properties of the proposed vector space. Some participants are providing guidance on how to approach the problem, while others express confusion about the concepts involved. There is an ongoing exploration of whether specific examples can demonstrate that the vector space axioms are not satisfied.

Contextual Notes

There is uncertainty regarding the definition of the coefficient set for the polynomials, with assumptions being made about the underlying field. Participants are also grappling with the implications of using polynomial multiplication as the addition operation, which complicates the analysis of vector space properties.

brinethery
Messages
22
Reaction score
0

Homework Statement



Determine if this set is a vector space. Either show that the necessary properties are satisfied, or give an example showing that at least one of them is not.

-The set P of all polynomials, with the usual definition of scalar multiplication, but with addition defined as polynomial multiplication (so f + g (warped addition) is equal to the product of f and g).

Homework Equations





The Attempt at a Solution



I know that scalar multiplication holds up, but I don't understand what to do with the polynomial multiplication part.
 
Physics news on Phys.org
Hopefully this gets you started. For associativity of addition:

Let V be the set of all polynomials, and let f, g, and h be polynomials in V such that f + g = fg, f+h = fh, g+h = gh.

Associativity of addition says that if V is a vector space, then it satisfies the property that f + (g+h) = (f+g) + h:

f + (g + h) = f + gh = f(gh) = (fg)h = (f + g)h = (f+g) + h. Thus, V holds for the associativity property of addition.

Try using the same procedure for the remaining 3 properties.
 
well, for one thing, you have to define the coefficient set for the polynomials (or, tell us what underlying field you are considering for your proposed vector space).

since you don't say, my guess is you mean the field of real numbers, but this is just that: a guess.

if you suspect one of the axioms does not hold, it suffices to give a single counter-example for that axiom.
 
brinethery said:

Homework Statement



Determine if this set is a vector space. Either show that the necessary properties are satisfied, or give an example showing that at least one of them is not.

-The set P of all polynomials, with the usual definition of scalar multiplication, but with addition defined as polynomial multiplication (so f + g (warped addition) is equal to the product of f and g).

Homework Equations



The Attempt at a Solution



I know that scalar multiplication holds up, but I don't understand what to do with the polynomial multiplication part.

Put f and g both equal to the polynomial x. What is 2f + 2g in your warped addition? What should it be in a vector space?
 
Deveno said:
well, for one thing, you have to define the coefficient set for the polynomials (or, tell us what underlying field you are considering for your proposed vector space).

since you don't say, my guess is you mean the field of real numbers, but this is just that: a guess.

if you suspect one of the axioms does not hold, it suffices to give a single counter-example for that axiom.

Yes, it is a vector space. Sorry about that.
 
Dick said:
Put f and g both equal to the polynomial x. What is 2f + 2g in your warped addition? What should it be in a vector space?

Sorry, I REALLY don't get vector spaces. But I'll take a guess at your question.

Wouldn't you factor out the 2 and go from there?

2(f+g) = 2(f*g), they don't equal each other and therefore polynomial addition doesn't hold.

That is just a guess. So I'm thinking this would show that it's not a vector space.
 
brinethery said:
Sorry, I REALLY don't get vector spaces. But I'll take a guess at your question.

Wouldn't you factor out the 2 and go from there?

2(f+g) = 2(f*g), they don't equal each other and therefore polynomial addition doesn't hold.

That is just a guess. So I'm thinking this would show that it's not a vector space.

Ooops. I really picked the wrong number to scalar multiply there. Sorry. Try 3f+3g. What is 3f+3g (warped addition) and what is 3(f+g) (warped addition). They are supposed to be equal in a vector space. Just answer those and I think you'll have it. This is a bit more confusing than usual because of (warped addition) thing. It does make it hard to follow.
 
Last edited:
So what you're saying is that 3f+3g does not equal 3(f*g), right?

For example, let's say f=2 and g=5

(3)2+(3)5 does not equal 3(2*5) ?

Forgive me for my ignorance, this is a weird subject for me.
 
brinethery said:
So what you're saying is that 3f+3g does not equal 3(f*g), right?

For example, let's say f=2 and g=5

(3)2+(3)5 does not equal 3(2*5) ?

Forgive me for my ignorance, this is a weird subject for me.

It's a weird (but legitimate) question. 3f+3g (warped addition) is (3f)*(3g). 3(f+g) (warped addition) is 3(f*g). They are just substituting the '*' operation for the '+' operation. Are they equal?
 
  • #10
brinethery said:
So what you're saying is that 3f+3g does not equal 3(f*g), right?

For example, let's say f=2 and g=5

(3)2+(3)5 does not equal 3(2*5) ?

Forgive me for my ignorance, this is a weird subject for me.

To stick with your original example, it's because (3)2*3(5) is not the same as 3(2*5).
 
  • #11
I see where you're going and since I'm so unsure, I was just trying to confirm it :-)

Thank you again. I am so lost that even my questions don't make sense!
 
  • #12
At this point I'm hoping to get through the class by the skin of my teeth :-/
 
  • #13
brinethery said:
At this point I'm hoping to get through the class by the skin of my teeth :-/

Most questions shouldn't be this confusing. (warped addition) is odd. You probably won't see it again. Have a little more confidence.
 

Similar threads

Replies
8
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
Replies
9
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K