Linear Algebra Matrix Limits/Stochastic Process

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SUMMARY

The discussion focuses on a stochastic process involving diaper liners, modeled using a transition matrix to determine the long-term proportions of new, once-used, and twice-used liners. The transition matrix A is defined as A = (1/3, 1/3, 1 | 2/3, 0, 0 | 0, 2/3, 0). The initial state vector is v = (1, 0, 0). To find the limiting state probabilities, participants suggest solving a linear system of equations derived from the matrix, as direct computation using tools like WolframAlpha is inefficient due to timeout issues.

PREREQUISITES
  • Understanding of stochastic processes and Markov chains
  • Familiarity with transition matrices and state vectors
  • Knowledge of linear algebra, specifically solving systems of equations
  • Experience with computational tools for matrix operations
NEXT STEPS
  • Study the properties of Markov chains and their long-term behavior
  • Learn how to derive and solve linear systems using matrix algebra
  • Explore computational tools like MATLAB or Python's NumPy for matrix calculations
  • Investigate the application of transition matrices in real-world scenarios beyond diaper liners
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This discussion is beneficial for students and professionals in mathematics, particularly those studying linear algebra and stochastic processes, as well as anyone interested in practical applications of Markov chains in modeling systems.

lutheranian
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Homework Statement



A diaper liner is placed in each diaper worn by a baby. If, after a diaper change, the liner is soiled, then it is discarded and replaced by a new liner. Otherwise, the liner is washed with the diapers and reused, except that each liner is discarded and replaced after its third use (even if it has never been soiled). The probability that the baby will soil any diaper liner is one third. If there are only new diaper liners at first, eventually what proportions of the diaper liners being used will be new, once used, and twice used? Hint: Assume that a diaper liner ready for use is in one of the three states: new, once used, or twice used. After its use, it then transforms into one of the three states described

Homework Equations




If A is a transition matrix and v is the initial state vector and

lim Am = L as m -->[itex]\infty[/itex] then eventual state is Lv

The Attempt at a Solution



I set up the transition matrix with the first column/row corresponding to new liners, the second to once-used, and the third to twice-used, resulting in the following:

A= (1/3, 1/3, 1| 2/3, 0, 0 | 0, 2/3, 0)

The initial vector is v= (1, 0, 0)

I tried finding the limit of Am as m --> [itex]\infty[/itex] using wolframalpha (which is allowed because the homework problems have messy numbers) but the computation times out every time.
 
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You can get the limiting state-probabilities by setting up and solving a linear system of 3 equations in 3 unknowns. Using the standard convention (with the ROWS summing to 1---not the columns, as you have chosen), the limiting (row) vector, u, satisfies u = u.A and sum u(j) = 1. Omit one of the three equations u(j) = sum_{k} u(k)*A(k,j), j=1,2,3, and replace it by the normalizing condition sum u = 1.

RGV
 
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