Linear Algebra - Polynomial Subsets of Subspaces

Click For Summary
SUMMARY

The discussion centers on identifying which subsets of the polynomial space P_{2} (degree 2 or below) qualify as subspaces based on specific conditions. The subsets in question are: (a) polynomials where a_{1} = 0 and a_{0} = 0, (b) polynomials where a_{1} = 2a_{0}, and (c) polynomials where a_{2} + a_{1} + a_{0} = 2. It is established that subset (b) is a subspace as it includes all polynomial terms and satisfies closure under addition and scalar multiplication, while subsets (a) and (c) do not meet the necessary criteria for subspaces.

PREREQUISITES
  • Understanding of polynomial functions in P_{2}
  • Knowledge of vector space properties, specifically closure under addition and scalar multiplication
  • Familiarity with the definitions of subspaces in linear algebra
  • Ability to manipulate and analyze polynomial equations
NEXT STEPS
  • Study the properties of vector spaces and subspaces in linear algebra
  • Learn about closure properties in vector spaces
  • Explore examples of polynomial subspaces and their characteristics
  • Review the definitions and theorems related to linear combinations and span
USEFUL FOR

Students and educators in linear algebra, mathematicians focusing on polynomial functions, and anyone seeking to deepen their understanding of vector spaces and subspace criteria.

kaitamasaki
Messages
20
Reaction score
0

Homework Statement


Which one of the following subsets of [tex]P_{2}[/tex] (degree of 2 or below) are subspaces?
a) [tex]a_{2}t^{2} + a_{1}t + a_{0}[/tex], where [tex]a_{1} = 0[/tex] and [tex]a_{0} = 0[/tex]
b) [tex]a_{2}t^{2} + a_{1}t + a_{0}[/tex], where [tex]a_{1} = 2a_{0}[/tex]
c) [tex]a_{2}t^{2} + a_{1}t + a_{0}[/tex], where [tex]a_{2} + a_{1} + a_{0} = 2[/tex]

Homework Equations


The Attempt at a Solution



First of all I don't even know if the question means only ONE of the three choices is a subspace, or whether I have to decide whether each of them are subspaces or not.

I know that in order for a subset to be a subspace, it must be closed under addition and multiplication.

a) would only have [tex]a_{2}t^{2}[/tex], but doesn't have the other degrees... is it not a subspace then? It is closed under addition ([tex](a_{2}+a_{2})t^{2})[/tex] and and multiplication. Is the question implying the coefficient a2 doesn't change? So you can't have (a2)t^2 + (-a2)t^2 = 0 right?

b) I have all the terms for each degree, so I'm guessing it is a subspace?

c) I have no clue how to do this one. My guess is that I can factor out the 2 and it becomes 2([tex]t^{2} + t + 1[/tex]), but if I add two of these together, I would get 4([tex]t^{2} + t + 1[/tex]), so don't know if that is still in the subspace... does the scalar in front matter or not?
 
Last edited:
Physics news on Phys.org
Don't guess: appeal to definitions and theorems! They give you a specific list of things to check, right? You say "it must be closed under addition and multiplication". What does that actually mean?


Is that really the exact statement of the problem? It looks very sloppy to me. :frown: What they mean is surely something like:

a) The set of all vectors of the form a2t2 + a1t1 + a0 (where a2, a1, and a0 are scalar-valued dummy variables) for which a1 = 0 and a0 = 0.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
9
Views
2K
Replies
5
Views
2K
Replies
5
Views
3K
  • · Replies 1 ·
Replies
1
Views
1K