Linear Conservation of Momentum

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SUMMARY

The discussion focuses on a linear conservation of momentum problem involving an 18-kg shell fired at a muzzle velocity of 185 m/s at an angle of 33 degrees. Upon reaching the peak of its trajectory, the shell explodes into two equal mass fragments, with one fragment falling vertically and having a horizontal speed of zero. The conservation of momentum equation m_Tv_i_x = m_1v_1_x + m_2v_2_x is applied to determine the horizontal speed of the other fragment, leading to a definitive calculation of its velocity based on the initial conditions.

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am08
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A 18-kg shell is fired from a gun with a muzzle velocity 185 m/s at 33o above the horizontal. At the top of the trajectory, the shell explodes into two fragments of equal mass. One fragment, whose speed immediately after the explosion is zero, falls vertically. What is the horizontal speed of the other fragment?
 
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Well, I believe that the way to solve this problem is by first finding the x-component of the initial velocity.

Since this is an explosion momentum problem:

m_Tv_i_x = m_1v_1_x+m_2v_2_x

And one of the terms on the right will cancel out since v_x=0 for one of them.
 
Use conservation of momentum.
 

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