Linear Damping Model: Help Solving Forces & Displacement Vector

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SUMMARY

The discussion focuses on solving problems related to a linear damping model, specifically in the context of a seismograph. Key points include the identification of forces acting on a particle, such as weight (W), air resistance (R), and spring force (H), and the formulation of equations of motion using Newton's second law. The participants clarify the relationships between these forces and the displacement vector, ultimately leading to the derivation of a differential equation that describes the system's behavior. Additionally, the discussion touches on the amplitude ratio of steady-state oscillations, providing a formula for M in terms of various parameters.

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moolimanj
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Hi All

This is my first post and I was hoping that someone could help. I have the following attached question regarding a linear damping model (in this case a seismograph).

(1) Draw a force diagram.

If W=weight, R= air resistance, and H= spring force, then I get W pointing down and both R and H pointing up. Is this right? Should there be another force as well (i.e. at the pointer and in the damper)

(2) Express forces on particle in terms of given variables and parameters and unit vector i.

I'm confused on this one. Can someone help?

(3) Express displacement vector p of mass relative to origin in terms of x, y, d and i. Write down equation of motion of particle, and hence show that x(t) satisfies the differential equation md^2x/dt^2 +rdx/dt+kx=mg+kl+md^2y/dt^2


For (3) I get the following (can someone check):

We are applying Newton's second law here, but there is one extra feature: the acceleration of the box comes in as relative motion. So whatever expression we get for the net force, we need to add a m d^2y / dt^2 to it. I will simply put that into the equation "by hand."

I have a coordinate system with the positive direction upward. So in the Free Body diagram of the mass there is a weight (w) acting downward, a spring force (f) acting upward, and a resistive force (R) from the piston acting downward.

f = kl = k(x - l_0)

w = mg

R = r \frac{dx}{dt}

So Newton's second in the vertical direction gives:
m \frac{d^2x}{dt^2} = -mg + k(x - l_0) - r \frac{dx}{dt} + m \frac{d^2y}{dt^2}

(4) Suppose displacement vector y is given by y=acos(ft), where a is input amplitude, and f is omega (forcing angular frequency). Show that M, the given ratio of the amplitude A of the steady state output oscillations to a is given by:

M=A/a=mf^2/SQRT((k-mf^2)^2+r^2f^2)

I haven't got a clue with this one. Any help would be greatly appreciated

Many thanks
 

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For part (2), am I right in thinking that the following are the forces acting on the particle:

W=-mgi
R=rxi
H=k(l-l0)s


note the x term in R has a dot on the top (ie function of velocity I think
 
This block really sucks.

The dot means the its the derivative of x(t)...

I think somebody might be more inclined to help if you didnt present the problems in Latex code.

Can somebody help? Please?
 

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