Understanding Linear Expansivity: Tips for Finding L2 with Ease

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Finding L2 using linear expansivity can be confusing due to the complexity of the formulas involved. The correct formula to calculate L2 is l2 = l1[1 + α(T2 - T1)], which derives from the initial equation. Users are advised to carefully follow the order of operations and avoid adding lengths to pure numbers, which leads to errors. The process involves calculating the temperature difference, multiplying it by the linear expansivity and the original length, and then adding this change to the original length. Understanding these steps can help alleviate the stress of solving for L2.
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ever since i was taught this along with the other expansivities its been giving me trouble. the formula is for looking for the expansivity and then you'd be seeing questions telling u to look for L2.. and L2 is quite hard to find because the formula is not straight forward...

please anyone,, how can i find L2 without all this stress
 
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Exactly which formula are you referring to?
 
l2-l1<divided by> l1(temperature2 - temperature1)= e divided by l1*final temperature... try writing it with a pen for better understanding
 
Eke said:
l2-l1<divided by> l1(temperature2 - temperature1)= e divided by l1*final temperature... try writing it with a pen for better understanding

You mean
\frac{l_2-l_1}{l_1(T_2-T_1)}=\alpha

What is the question? "How to solve for l2" ?
 
yeah yeah.. how to solve for l2... my textbook gave me this formula..
l2=l1(1+linearexpansivity<T2-T1>)
let me write it in text...
l2=l1(1+linearexpansivity...times <T2-T1>)
and the formula is not as straight forward as it seems
 
Actually this second form is the most common one.
l_2=l_1[1+\alpha(T_2-T_1)]
It follows from the first one from simple algebraic manipulation.
I still don't see what your problem is.
Do you want to plug in and find l2?
 
yes.. that's the formula...
first i plus l1 with 1 because multiplying it wouldn't make much sense..
then i add the linear expansivity as told in the formula...
then multiply all that with my final temperature...
but still my answer is diff. from my textbook...
am i doing it wrong
 
Eke said:
yes.. that's the formula...
first i plus l1 with 1 because multiplying it wouldn't make much sense..
No, actualy what you say here does not make sense.
You cannot add (in a meaningful way) a length with a pure number.
I am afraid you need to brush up your algebra a bit. About precedence of operations and brackets.

But here is how it may be done here (it's not the only way):
Open the bracket and you will have
l_2=l_1+l_1\alpha(T_2-T_1)
So find the temperature difference ΔT=(T2-T1) and them multiply this ΔT by α and l1.
This will be by how much the length have changed.
Finally add this to the original length, l1. And you will have l2.
 
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