Linear Independence: u,v,w Homework Ques.

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Homework Help Overview

The discussion revolves around the concept of linear independence in the context of vectors u, v, and w. The original poster presents a question regarding the linear independence of two sets of vectors derived from u, v, and w.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster expresses uncertainty about how to approach the problem and questions the reasoning behind the answers provided in their textbook. Some participants suggest starting with the definition of linear independence and exploring the relationships between the vectors through coefficients.

Discussion Status

Participants are actively engaging with the definitions and attempting to derive conditions for linear independence. Some have provided specific examples of coefficients that lead to linear dependence, while others are exploring the implications of these findings. There is a focus on understanding the reasoning behind the independence or dependence of the given sets of vectors.

Contextual Notes

The original poster notes that the question is from a textbook and expresses confusion about the differing answers for the two sets of vectors. There is an implication that the discussion is constrained by the need to explain the reasoning behind the answers rather than simply stating them.

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Homework Statement



If vectors u v & w ARE linearly independent are:

a) u+v, u+w, v+w
b) u-v, u-w, v-w

The attempt at a solution

I don't really know where to start with this. It isn't homework. It is just one of the questions out of my textbook(ch 2.3 #43 linear algebra by poole 3rd ed).

So the answers are a) yes b) no. But the question says to explain why and the back of the book just says yes and no. I don't understand why either would be different.

I guessed and said the first one would be independent. But guessing doesn't really do anything in the real world. other then gives you a small percentage to be right.

Any help would be muchly appreciated
 
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Start with the definition. Can you or can you not find constants ##A,B,C## not all zero such that$$
A(u+v) + B(u+w) + C(v+w)=0$$
 
LCKurtz said:
Start with the definition. Can you or can you not find constants ##A,B,C## not all zero such that$$
A(u+v) + B(u+w) + C(v+w)=0$$

$$u(A+B) + v(A+C) + w(B+C) = 0$$

$$u(A+B) + v(-A+C) + w(-B-C) = 0 $$
A=1, B=-1, C=1.
1+-1=0, -1+1=0, --1-1=0

So.. By inspection.. I can make the second one a 0 without zero's.. So that would mean. They are now linearly dependent. But how would I calculate that? I don't know how to put a proof vector into a real formula.
 
JeeebeZ said:
$$u(A+B) + v(A+C) + w(B+C) = 0$$

$$u(A+B) + v(-A+C) + w(-B-C) = 0 $$
A=1, B=-1, C=1.
1+-1=0, -1+1=0, --1-1=0

So.. By inspection.. I can make the second one a 0 without zero's.. So that would mean. They are now linearly dependent. But how would I calculate that? I don't know how to put a proof vector into a real formula.

In the first case, you need A+B=0, A+C=0, B+C=0, because these are the coefficients of u, v and w, and u,v,w are linearly independent. The only solution is A = B = 0, so that means the original set {u+v,u+w,v+w} is linearly independent as well.

In the second case you need A+B=0, -A+C=0, -B-C=0. There is a nonzero solution, so the set {u-v,u-w,v-w} is linearly dependent.

RGV
 

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