# Linear Inverting Amplifier Help

## Homework Statement

A linear inverting amplifier has these characteristics:
-5.0V < vo < +5.0V Av=35 dB
The output rails at -5.0V and +5.0V That is, the amplifier outputs no voltage larger in magnitude than 5.0V.

What is the gain in V/V?
What is the output if vi=-8.0V?

Av = vo/vi
Av = 20log|Av|

## The Attempt at a Solution

Av = 35db
35/20 =log|Av| => Av = e^(7/4) V/V
vo = Av * vi => (-8.0V) * e^(7/4)
but since this is out of the -5V to 5V range, it would just be 5V

Does this look right?

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gneill
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## Homework Statement

A linear inverting amplifier has these characteristics:
-5.0V < vo < +5.0V Av=35 dB
The output rails at -5.0V and +5.0V That is, the amplifier outputs no voltage larger in magnitude than 5.0V.

What is the gain in V/V?
What is the output if vi=-8.0V?

Av = vo/vi
Av = 20log|Av|

## The Attempt at a Solution

Av = 35db
35/20 =log|Av| => Av = e^(7/4) V/V
Watch it! The log is base 10, not base e. And you should be able to write a numerical value for a result.

vo = Av * vi => (-8.0V) * e^(7/4)
but since this is out of the -5V to 5V range, it would just be 5V
Yup. The input already exceeds the output range and the gain is greater than unity.