Linear model of air resistance

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SUMMARY

The discussion focuses on modeling the velocity and displacement of paper shapes under air resistance, defined by the equation R = kv, where R is air resistance and v is velocity. The user has derived equations for velocity and displacement but is struggling to determine the constant k, which relates air resistance to velocity. The terminal velocity is identified as mg/k, where m is the mass of the paper cup. The user seeks assistance in calculating k based on experimental results and theoretical equations.

PREREQUISITES
  • Understanding of Newton's Second Law of Motion
  • Familiarity with differential equations and integrating factors
  • Knowledge of terminal velocity concepts
  • Basic principles of air resistance and its mathematical modeling
NEXT STEPS
  • Calculate the constant k using experimental data and the equation for terminal velocity, k = mg/v_terminal.
  • Explore the effects of varying mass on terminal velocity in air resistance models.
  • Investigate the impact of different paper shapes on drag coefficient and air resistance.
  • Learn about numerical methods for solving differential equations in physics simulations.
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding the dynamics of motion under air resistance, particularly in experimental and theoretical contexts.

cenarme
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Homework Statement


Hi,
I have to model the velocity and displacement of different paper shapes assuming that air resistance, R is proportional to velocity, v.

I have also conducted an experiment, and the equation of the line
h = 1.532t - 0.366
Where h is the height the paper shape was dropped from, if t is the time taken for it to reach the ground.

Model:
R = kv
Assuming that the only forces acting on the cup are it's mg downwards and R upwards.
And that the motion is vertical only.

when t=0, v=0 and x=0

I have found the equations for v and x in terms of t. The problem I have is finding k.

k= constant in the the assumption R is prop to v.
mg= weight of paper cup
R= air resistance
dv/dt = acceleration
x= displacement
v= velocity of the paper cup

Downwards is taken as positive.

I will go through what I have so you know what I am working with and the nature of the problem, but ultimately the problem I have with is k.

Homework Equations



N[II] gives : m(dv/dt) = mg -kv

(dv/dt) + (k/m)*v = g

Using an integrating factor: I = e^(kt/m)

So d(v*e^[kt/m])/dt = ∫ge^(kt/m)dt

Finishing this and using the initial conditions:

v = [mg/k]*(1-e^[-kt/m])

Integrating this we get displacement:

x = [mg/k]*(t+(m/k)e^(-kt/m)+c)

Using initial conditions:

x= [mg/k]*(t+(m/k)*[e^(-kt/m)-1])

The Attempt at a Solution


I know that t -> ∞ v-> mg/k [which will be an asymptote when plotted]

So the terminal velocity = mg/k

I also know that the x against t graph will look like a curve with an increasing gradient, until the time at which the terminal velocity is reached. At this time the gradient will become constant.

Ok so now we find k--- how?

Thanks in advance.
 
Physics news on Phys.org
Your experimental result has h = ct+d. So for large t, h ~ ct. Doesn't that give you your terminal velocity? And presumably you know m.
 

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