Bored, a boy shoots his pellet gun at a piece of cheese that sits, keeping cool for dinner guests, on a massive block of ice. On one particular shot, his 1.1 g pellet gets stuck in the cheese, causing it to slide 25 cm before coming to a stop. If the muzzle velocity of the gun is 76 m/s and the cheese has a mass of 136 g, what is the coefficient of friction between the cheese and ice? Relevant equations: Momentum = Mass * Velocity This would be an example of an inelastic collision where the two objects stick together. The KE is not conserved. I converted the mass of the pellet and the cheese to kg. Mass of pellet = .0011kg Mass of cheese = .136kg Momentum of the pellet = .0011kg * 76m/s = .0836 kg m/s The momentum will be conserved because there is no external forces. This is as far as I got, can someone tell me how should I approach this next? Thanks.