Linear Operator: Eigenfunctions and Boundary Conditions for Energy Calculation

[lokofer]

let be the linear operator: (Hermitian ??)

L = -i(x\frac{d}{dx}+1/2)

then the "eigenfunctions" are y_{n} (x)=Ax^{i\lambda _{n} -1/2

then my question is how would we get the energies imposing boundary conditions? (for example y(0)=Y(L)=0 wher L is a positive integer )...

 

[HallsofIvy]

Energies? That is certainly not a Hamiltonian. In any case, since it is a first order operator, you can't satisfy two boundary conditions, only one.