Linear operator, its dual, proving surjectivity

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Discussion Overview

The discussion revolves around proving the surjectivity of a continuous linear operator between Banach spaces, specifically exploring the equivalence between the surjectivity of the operator and the properties of its dual operator. Participants are examining theoretical aspects of functional analysis.

Discussion Character

  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • One participant states the equivalence to prove: a continuous linear operator $$T$$ is surjective if and only if its dual $$T^*$$ is injective and the image of $$T^*$$ is closed.
  • The same participant references a previously proven similar statement involving the image of $$T$$ instead of $$T^*$$, using the facts about the closure of the image and the kernel relationships.
  • Another participant mentions a classical theorem by Banach regarding the closed range of bounded linear operators and their adjoints, suggesting this theorem may be crucial for the problem at hand.
  • A later reply suggests a resource, Yosida's Functional Analysis, as an alternative reference for the theorem mentioned.

Areas of Agreement / Disagreement

Participants appear to be exploring the problem collaboratively, with some agreement on the relevance of Banach's theorem, but no consensus on the proof of the equivalence itself. The discussion remains unresolved regarding the specific proof steps needed.

Contextual Notes

Participants have not fully detailed the assumptions or definitions they are using, and the discussion does not clarify the specific mathematical steps required to establish the equivalence.

Linux
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Let $$T: X \rightarrow Y$$ be a continuous linear operator between Banach spaces.

Prove that $T$ is surjective $$\iff$$ $$T^*$$ is injective and $$im T^*$$ is closed.

I've proven a "similar" statement, with $$imT^*$$ replaced with $$imT$$.

There I used these facts: $\overline{imT}= ^{\perp}(kerT^*)$ and $\overline{imT^*} \subset (kerT)^{\perp}$

However, I do not know how to prove the equivalence above.

Could you give me some ideas?
 
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Linux said:
Let $$T: X \rightarrow Y$$ be a continuous linear operator between Banach spaces.

Prove that $T$ is surjective $$\iff$$ $$T^*$$ is injective and $$im T^*$$ is closed.

I've proven a "similar" statement, with $$imT^*$$ replaced with $$imT$$.

There I used these facts: $\overline{imT}= ^{\perp}(kerT^*)$ and $\overline{imT^*} \subset (kerT)^{\perp}$

However, I do not know how to prove the equivalence above.

Could you give me some ideas?
A classical theorem of Banach (you'll find it somewhere in his book Opérations linéaires – it's a consequence of the open mapping theorem) says that a bounded linear operator between Banach spaces has closed range if and only if its adjoint also has closed range. I think that will be the key ingredient in your problem.
 
Thank you. Could you tell me where I can find a proof of this theorem, apart from Stefan Banach's book (which is in French)?
 
Last edited:
(From my phone by Tapatalk)
Try Yosida's Functional Analysis.
 
Thanks. I've just found the book.
 

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