Linear operator, its dual, proving surjectivity

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SUMMARY

The discussion centers on proving the surjectivity of a continuous linear operator $$T: X \rightarrow Y$$ between Banach spaces, specifically the equivalence between surjectivity and the conditions that the adjoint operator $$T^*$$ is injective and the image $$im T^*$$ is closed. Key facts referenced include the relationship between the image and kernel of the operators, specifically $$\overline{imT}= ^{\perp}(kerT^*)$$ and $$\overline{imT^*} \subset (kerT)^{\perp}$$. A classical theorem by Banach states that a bounded linear operator has a closed range if and only if its adjoint also has a closed range, which is crucial for this proof.

PREREQUISITES
  • Understanding of continuous linear operators between Banach spaces
  • Familiarity with adjoint operators and their properties
  • Knowledge of the open mapping theorem in functional analysis
  • Concepts of closed ranges and kernels in linear algebra
NEXT STEPS
  • Study the open mapping theorem in functional analysis
  • Learn about the properties of adjoint operators in Banach spaces
  • Read Yosida's "Functional Analysis" for further insights on closed ranges
  • Explore proofs of Banach's theorem on closed ranges and adjoint operators
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Mathematicians, particularly those specializing in functional analysis, graduate students studying linear operators, and researchers exploring properties of Banach spaces.

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Let $$T: X \rightarrow Y$$ be a continuous linear operator between Banach spaces.

Prove that $T$ is surjective $$\iff$$ $$T^*$$ is injective and $$im T^*$$ is closed.

I've proven a "similar" statement, with $$imT^*$$ replaced with $$imT$$.

There I used these facts: $\overline{imT}= ^{\perp}(kerT^*)$ and $\overline{imT^*} \subset (kerT)^{\perp}$

However, I do not know how to prove the equivalence above.

Could you give me some ideas?
 
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Linux said:
Let $$T: X \rightarrow Y$$ be a continuous linear operator between Banach spaces.

Prove that $T$ is surjective $$\iff$$ $$T^*$$ is injective and $$im T^*$$ is closed.

I've proven a "similar" statement, with $$imT^*$$ replaced with $$imT$$.

There I used these facts: $\overline{imT}= ^{\perp}(kerT^*)$ and $\overline{imT^*} \subset (kerT)^{\perp}$

However, I do not know how to prove the equivalence above.

Could you give me some ideas?
A classical theorem of Banach (you'll find it somewhere in his book Opérations linéaires – it's a consequence of the open mapping theorem) says that a bounded linear operator between Banach spaces has closed range if and only if its adjoint also has closed range. I think that will be the key ingredient in your problem.
 
Thank you. Could you tell me where I can find a proof of this theorem, apart from Stefan Banach's book (which is in French)?
 
Last edited:
(From my phone by Tapatalk)
Try Yosida's Functional Analysis.
 
Thanks. I've just found the book.
 

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