- #1
knightmetal
- 10
- 0
Hello,
I'm given this linear transformation and I'm asked to do the typical calculations (kernel, image, dimensions, etc.) but there's one thing I'm not sure I understand, here's the exercise:
f(1,0,0)=(-1,-2,-3)
f(0,1,0)=(2,2,2)
f(0,0,1)=(0,1,2)
a) Is f invertible?
b)Find a basis of Ker(f) and a basis of Im(f)
c)Find eigenvalues, eigenvectors. is f diagonalizable?
d) Solve the system f^2(x)=0
Can anybody point me in the right direction on how to solve d) ?
Thanks a lot
I'm given this linear transformation and I'm asked to do the typical calculations (kernel, image, dimensions, etc.) but there's one thing I'm not sure I understand, here's the exercise:
f(1,0,0)=(-1,-2,-3)
f(0,1,0)=(2,2,2)
f(0,0,1)=(0,1,2)
a) Is f invertible?
b)Find a basis of Ker(f) and a basis of Im(f)
c)Find eigenvalues, eigenvectors. is f diagonalizable?
d) Solve the system f^2(x)=0
Can anybody point me in the right direction on how to solve d) ?
Thanks a lot