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## Homework Statement

For the network of constant current shown in Figure 4 it is known that R1 = 50 Ω and , R = 10 Ω. When the switch P is

in the 1-position , current I = 50 mA and Ip = 70 mA known i . When the switch P is in

the 2-position , current I' = 40 mA and Ip' = 90 mA are known . Determine the current Ip''

when the switch switches to the third position.

## Homework Equations

## The Attempt at a Solution

By linearity and superposition theorem we have a linear network and if we have our active load network we can write I = xU + y , where current I is the response and voltage U represents excitation , constants x and y are determined by the resistance of the active network ,where x has dimension of A/V and y has dimension of A.

By solving equation 1 and equation 2 I get that,

x = 0.2 and y = -0.23,

for the 3rd equation I get:

Ip" = xU1 + y = 0.2 U1 - 0.23

I have two unknowns Ip" ,U1 and only 1 equation.

What am I doing wrong?