Linearization of f(x)=x^1/3 at a=-64

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Homework Help Overview

The discussion revolves around the linearization of the function f(x) = x^(1/3) at the point a = -64. Participants are exploring the application of the linearization formula and the calculation of the derivative at the specified point.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to apply the linearization formula and calculate the function value and derivative at a = -64. Some participants question the correctness of the derivative value and its application in the linearization expression.

Discussion Status

The discussion includes verification of the derivative calculation and its use in the linearization formula. There is a back-and-forth regarding the sign and value of the derivative, indicating some uncertainty but also a collaborative effort to clarify the approach.

Contextual Notes

Participants are working within the constraints of the problem as posed, focusing on the specific function and point of linearization without additional context or external references.

Rasine
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Find the linearization of f(x)= x^1/3 at a=-64

so i am trying to use f(x)=f(a)+f'(a)(x-a)

f(a)=-4
f'(x)=1/3(x^-2/3)
f'(a)=-1/48

so i get -4+1/48(x+64)


is that right?
 
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Well, you say f'(a)=-1/48 and you put +1/48 into the answer. Which is it?
 
it is the latter
 
Keerect. Then everything is ok.
 

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