An object 2.71 * 10-2m tall is 0.14m in front of a convex mirror that has a radius of curvature 42cm. Calculate the position and height of the image, is the image inverted or upright?
Well, I've stated that I'm using the ray model of light.
As far as I can deduce, the equation Focal length = R/2, 1/u + 1/v = 1/f.
magnification = v/u.
Where u = distance from mirror to object
v = distance from mirror to image
f = focal length.
r = center of curvature
The Attempt at a Solution
I have found the focal length to be 0.21m, and the image distance being 0.07m by rearranging 1/u + 1/v = 1/f.
I have found the height of the image to be half the original height.
I'm not sure if this is right, as I feel I have made up how to go about it, any pointers?