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## Homework Statement

An object 2.71 * 10

^{-2}m tall is 0.14m in front of a convex mirror that has a radius of curvature 42cm. Calculate the position and height of the image, is the image inverted or upright?

## Homework Equations

Well, I've stated that I'm using the ray model of light.

As far as I can deduce, the equation Focal length = R/2, 1/u + 1/v = 1/f.

magnification = v/u.

Where u = distance from mirror to object

v = distance from mirror to image

f = focal length.

r = center of curvature

## The Attempt at a Solution

I have found the focal length to be 0.21m, and the image distance being 0.07m by rearranging 1/u + 1/v = 1/f.

I have found the height of the image to be half the original height.

I'm not sure if this is right, as I feel I have made up how to go about it, any pointers?