- #1
QuarkCharmer
- 1,051
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Homework Statement
This is not a specific problem that I must complete, but I realized that I forgot how to solve these style problems!
Homework Equations
The Attempt at a Solution
For instance, off the top of my head:
[tex]3e^{x+1}=e^{x+2}[/tex]
I would divide both sides through by 5 to get:
[tex]3e^{x+1}=e^{x+2}[/tex]
^This should look like: 3e^(x+1)=e^(x+2), I don't know what is up with latex.
Then I would probably take the natural log of both sides, but that coefficient is messing up my idea. Can I do this?
[tex](x+1)ln3e = (x+2)lne[/tex]
[tex](x+1)ln3e = (x+2)[/tex]
[tex]xln3e + ln3e = x+2[/tex]
[tex]x(ln3e + ln3e) = x+2[/tex]
[tex]x(ln3e + ln3e) - x = 2[/tex]
[tex]x((ln3e + ln3e) - 1 = 2[/tex]
[tex]ln3e + ln3e - 1 = \frac{2}{x}[/tex]
If that is even possible, which I highly doubt, I am stuck.
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