Hey forum, thanks in advance to anyone who can explain this to me! 1. The problem statement, all variables and given/known data Find the derivative of each of the following: h(x) = 3e^sin(x + 2) 3. The attempt at a solution My friend and I worked through this together and solved for: h’(x) = (3e^sin(x + 2))(cos(x + 2)) Using my graphing calculator I have already confirmed this answer.. 2. Relevant equations What I need help with is just a little bit of light being shed on the concept.. My book says : the chain rule says the derivative of u^(-1) is (-1)u^(-2) u' so I get that.. my book also says: the derivative of the function f(x)=a^g(x), where a is a positive constant, is given by f'(x)=a^g(x) lna g'(x) so applying to the question above.. isnt 3e a positive constant.. so my question basically is.. when working this problem through.. is there a middle step where a 'lne' is established? I realize lne = 1 anyway.. but I'm just wondering for the sake of making sure I thoroughly understand. and if there is a middle step involving the natural logarithm(ln) why wouldnt it be ln3e I realize its not because that would change the answer that I already confirmed but I'm just struggling to understand why not.. cuz if a mid step with ln is involved.. 3 * e is a positive constant I thought so I'd figure it would be ln3e :S or another option is its lne * 3 which still equals 1.. anyway, I'm rambling now so if someone could please explain this to me I would really appreciate it!