- #1
franky2727
- 132
- 0
ive got integral[(2/(2-z))+(2/(1+2z))]dz=integral dv/v
then the next line is ln|v|=-2ln|2-z|+ln|1+2z|+c
when i equate this i get rid of the 2 as a common factor integrate the V side first and multiply through by 1/2 giving me ln|2-z|+ln|1+2z|=1/2ln|v| which i don't think is the same as what my answer shows me can someone point out where I am going wrong please
then the next line is ln|v|=-2ln|2-z|+ln|1+2z|+c
when i equate this i get rid of the 2 as a common factor integrate the V side first and multiply through by 1/2 giving me ln|2-z|+ln|1+2z|=1/2ln|v| which i don't think is the same as what my answer shows me can someone point out where I am going wrong please