Logic Gates (NAND to AND Gates)

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The discussion centers on the logic behind using two NAND gates to construct an AND gate. The confusion arises from the input representation of ( (XY)' (XY)' ) ' versus ((XY)') '. It is clarified that the second NAND gate receives (XY)' as input, acting as an inverter for the first gate's output. The output from the second gate simplifies to ( (XY)' ) ', which ultimately reduces to XY, demonstrating the equivalence of two NAND gates functioning as an AND gate. The conclusion affirms that the input can indeed be expressed as ((XY)') ', leading to the same result of XY.
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couldnt understand why the input is ( (XY)' (XY)' ) ' , IMO , it should be ((XY)' ) ' . because the 2nd logic gates receive (XY)' input from the first logic gates , and the second logic gates act as inverter for the first logic gates.
 

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I think they did that because the (XY)' is the input to the second gate and both inputs are tied together then they said (XY)'(XY)' and the second gates output is then ( (XY)' (XY)' ) ' which can be reduced to ( (XY)' ) ' and the double negative to simply XY so it shows that two NAND gates can be used to construct an AND gate.
 
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jedishrfu said:
I think they did that because the (XY)' is the input to the second gate and both inputs are tied together then they said (XY)'(XY)' and the second gates output is then ( (XY)' (XY)' ) ' which can be reduced to ( (XY)' ) ' and the double negative to simply XY so it shows that two NAND gates can be used to construct an AND gate.
Can I say the input is ((XY)' ) ' , which is also can be reduced to XY ?
 
Yes, I believe that's right.
 
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