Looking for help with Thermodynamics

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SUMMARY

The final pressure in an isolated container with two equal volumes of ideal gas, initially at pressure P, remains P after the partition is removed. This conclusion is derived from the principle that the partial pressures of the gases combine, resulting in a total pressure equal to the original pressure. The equation PV=nRT is applicable, confirming that while individual gas pressures may halve, their sum maintains the original pressure level.

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  • Understanding of ideal gas laws, specifically PV=nRT
  • Knowledge of pressure and volume relationships in thermodynamics
  • Familiarity with concepts of partial pressure
  • Basic principles of thermodynamic systems and isolation
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  • Investigate the effects of temperature changes on gas pressure and volume
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Students studying thermodynamics, physics enthusiasts, and anyone seeking to deepen their understanding of gas behavior in isolated systems.

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Homework Statement



An isolated container is divided into two equal volumes by partition. In each part of the container there is an ideal gas. They have the same pressure P. The partition is removed. Which of the following is the final pressure:
A: P/2
B:P
C:3P/2
D:2P

Homework Equations


PV=nRT (I assume)

The Attempt at a Solution



Well, I know the right answer is B, the answer key says so, but I am not sure why. I thought about using this equation PV/T = constant, therefore T = PV, and P=T/V, so if volume is doubled, and T is constant, then P will be halved. I am not sure if this is right. Any help? :)
 
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The partial pressure of both gases will be P/2 but the partial pressures add up, resulting in P.

ehild
 


Thank you so much :D!
 

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