Hepic said:
To=(time of moving object.)
T=(Time of standing object.)
^=power of number.
sqrt=square of number.(x^1/2)
Law of einstein say: T= To / ( sqrt( 1 - u^2/c^2 ) )
Lorentz law say: T= (To + u*Xo/c^2) / ( sqrt( 1 - u^2/c^2 ) )
Why there is difference??
Is for other things?? I thought is for the same reasons...
If you have two events [itex]e_1[/itex] and [itex]e_2[/itex] that take place at different times and locations, and you let [itex]\delta t[/itex] be the time between the events in one frame, frame [itex]F[/itex], and [itex]\delta x[/itex] be the distance between them in that frame, then in the other frame, frame [itex]F'[/itex], you have:
[itex]\delta t' = \dfrac{1}{\sqrt{1-u^2/c^2}} (\delta t - u\ \delta x/c^2)[/itex]
[itex]\delta x' = \dfrac{1}{\sqrt{1-u^2/c^2}} (\delta x - u\ \delta t)[/itex]
Now, let's look at two special cases:
Case 1: the two events take place at the same location, according to frame [itex]F[/itex].
In this case, [itex]\delta x = 0[/itex]. So the formula for [itex]\delta t'[/itex] becomes:
[itex]\delta t' = \dfrac{1}{\sqrt{1-u^2/c^2}} \delta t[/itex]
Case 2: the two events take place at the same location, according to frame [itex]F'[/itex].
In this case, [itex]\delta x' = 0[/itex]. This means that [itex]\delta x = u\ \delta t[/itex].
In this case, the formula for [itex]\delta t'[/itex] becomes:
[itex]\delta t' = \dfrac{1}{\sqrt{1-u^2/c^2}} (\delta t - u\ (u\ \delta t)/c^2)[/itex]
which simplifies to:
[itex]\delta t' = \sqrt{1-u^2/c^2} \delta t[/itex]