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x'=[itex]\gamma[/itex](x-vt) & x=[itex]\gamma[/itex](x'+vt')

I know that I can derive t'=[itex]\gamma[/itex](t-vx/c^2)... however I can't seem to make it fall out mathematically. The suggested method is to cancel x'. Can anyone help me out on the steps?

Much appreciated! :)

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# Lorentz transformations: how can I derive the time equation?

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