Ly on gravitation only one part

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Comets follow elliptical orbits, and the discussion revolves around calculating a comet's speed at a different distance from the sun using conservation of energy. The initial attempt to find the speed was marked incorrect, prompting a clarification on the use of conservation of momentum versus conservation of energy. The equations for kinetic and potential energy were presented, but confusion arose regarding the mass of the comet, with the assumption that it should be the mass of the sun. The conversation highlights the importance of correctly applying conservation principles in gravitational contexts. Understanding these concepts is crucial for solving problems related to celestial mechanics.
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urgently need help on gravitation only one part

Comets travel around the sun in elliptical orbits with large eccentricities. If a comet has speed 7.0 x 10^4 m/s when at a distance of 2.5 x 10^11 m from the center of the sun, what is its speed when at a distance of 9.0 * 10^10 m?
___________ m/s

Attempt
(7.0 x 10^4)(2.5 x 10^11)= v(9.0 * 10^10)
v = 194444.444

However, this answer was marked wrong.
 
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First: in what units is your v given?

The angular momentum is constant along the orbit, but its magnitude is r*v* sin(angle between the radius and the direction of the velocity). This angle is unknown. So use the conservation of momentum instead.

ehild
 


v is in m/s. And what do you mean by saying that i should use coservation of momentum. Isn't that what i did but it was marked wrong?
 


Sorry, I meant conservation of energy...

ehild
 


okay but if i use conservation of energy i still encounter a problem.

KE + PE = KE +PE
1/2mv^2 + (-GMm/r) = 1/2mV^2 + (-GMm/R)
1/2v^2 + (-GM/r) = 1/2V^2 + (-GM/R)

I know
v = 2 x 10^4 m/s
r= 3 x 10^11 m
R=4 x 10^10 m

but i still need to know what M, the mass of the comet is equal to.
 


Isn't M the mass of the sun?
 
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