Magnetic Field and Charged Particle Motion

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Homework Help Overview

The discussion revolves around a problem involving the motion of a charged subatomic particle in a magnetic field. The particle, initially moving southward, is affected by a magnetic field that points upward, causing it to change direction as it approaches a wall. Participants are tasked with determining the charge of the particle based on its motion and the forces acting on it.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between kinetic energy and velocity, questioning how the magnetic field influences the particle's motion. There are discussions about the nature of the force exerted by the magnetic field and whether it affects the particle's speed. Some participants consider the implications of centripetal force in this context.

Discussion Status

There is an ongoing exploration of the effects of magnetic fields on charged particles, with some participants providing clarifications on the nature of the forces involved. The discussion includes various interpretations of how the magnetic field interacts with the particle's motion, but no consensus has been reached on the specifics of the calculations or assumptions required.

Contextual Notes

Participants are working within the constraints of a homework problem, which may limit the information available and the assumptions that can be made. The problem setup includes specific parameters such as mass, kinetic energy, and the configuration of the magnetic field, which are under discussion.

phyvamp
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Homework Statement


Suppose a subatomic particle of mass m kg has kinetic energy K.E. a nJ and is moving southward toward a vertical wall. When the particle is distance d cm from the wall a magnetic field is turned on: it has magnitude b T and points upward. The particle turns westward so it just skims along the wall. Find q, the charge (magnitude and sign) of the particle, in C.

Homework Equations


dF=IdLB
F=qvB

The Attempt at a Solution


I attempt to use 1/2 mv^2 = K.E. to find initial velocity first, but the direction of velocity is changed due to magnetic field. the magnitude of the velocity will change also? and I do not know how to find out the force acted on particle due to magnitude field either. Does K.E.=∫ F*dx from xi=0 to xf=d to find out F works? is this F the same with force due to magnitude field? or actually I need to consider about gravity?
thank you for your help!
 
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What path does the charged particle follow due to the presence of the magnetic field?
 
phyvamp said:

Homework Statement


Suppose a subatomic particle of mass m kg has kinetic energy K.E. a nJ and is moving southward toward a vertical wall. When the particle is distance d cm from the wall a magnetic field is turned on: it has magnitude b T and points upward. The particle turns westward so it just skims along the wall. Find q, the charge (magnitude and sign) of the particle, in C.

Homework Equations


dF=IdLB
F=qvB

The Attempt at a Solution


I attempt to use 1/2 mv^2 = K.E. to find initial velocity first, but the direction of velocity is changed due to magnetic field. the magnitude of the velocity will change also? and I do not know how to find out the force acted on particle due to magnitude field either. Does K.E.=∫ F*dx from xi=0 to xf=d to find out F works? is this F the same with force due to magnitude field? or actually I need to consider about gravity?
thank you for your help!
A magnetic field produces a force at right angles to the direction of motion of a moving charge. The particulars are determined by a vector cross product of the velocity and field vectors, or through the application of the right- or left-hand rule.

As is the case for circular motion, which you must have studied previously, the acceleration is at right angles to the motion and so changes the direction of the velocity vector but not its magnitude (speed). So, think about centripetal force and the types of calculations that pertain to it.
 
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gneill said:
A magnetic field produces a force at right angles to the direction of motion of a moving charge. The particulars are determined by a vector cross product of the velocity and field vectors, or through the application of the right- or left-hand rule.

As is the case for circular motion, which you must have studied previously, the acceleration is at right angles to the motion and so changes the direction of the velocity vector but not its magnitude (speed). So, think about centripetal force and the types of calculations that pertain to it.

thank you for the explanation. So magnetic field will not change the magnitude of the velocity generally? or this question just a particular case since acceleration is at right angles to the motion?
 
phyvamp said:
thank you for the explanation. So magnetic field will not change the magnitude of the velocity generally? or this question just a particular case since acceleration is at right angles to the motion?
In general a magnetic field won't change the speed of a charged particle moving through it. Any force that a moving charge "feels" due to its interaction with a magnetic field is always perpendicular to its direction of travel. It can change it's direction of travel, but not its speed.

To investigate further it would be helpful to know about the properties of the vector cross product. That's the mathematical approach. You can also investigate the "right hand rule" or "left hand rule" practical embodiments of the cross product properties that are used in practice to determine the direction of the effects.
 
gneill said:
In general a magnetic field won't change the speed of a charged particle moving through it. Any force that a moving charge "feels" due to its interaction with a magnetic field is always perpendicular to its direction of travel. It can change it's direction of travel, but not its speed.

To investigate further it would be helpful to know about the properties of the vector cross product. That's the mathematical approach. You can also investigate the "right hand rule" or "left hand rule" practical embodiments of the cross product properties that are used in practice to determine the direction of the effects.

thanks again for the explanation.
 

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