helpmeplz!
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hey guys i have a question. i solved the problem but i don't understand how to do it.
Two perpendicular straight wires join in the ends of a semicircular loop of radius a = 11 cm, as shown in the figure above. If the current I =6 A, what is the resultant field at the center of the circular section?
http://gauss.vaniercollege.qc.ca/webwork2/NYBramakko/Magnetic_Field/6/?effectiveUser=0954278&displayMode=images&showOldAnswers=1&user=0954278&key=bIyLRnos5NmBC26Vl4DpQdlatGJalrsW
i know how to get the magnetic field due to the semi circle, but for the two finite wires, i know from the integral we get uo I/ 4piR (sin phi1 + sinphi2). But for me when i look at each section of wire, I see the angles going from 0 to 90 degrees, so phi one is 0 degrees and phi 2 is 90 degree. Doing that gives 0. But that is obviously not right. Why do we use 45 degrees i just don't understand it? Please anyone!
Two perpendicular straight wires join in the ends of a semicircular loop of radius a = 11 cm, as shown in the figure above. If the current I =6 A, what is the resultant field at the center of the circular section?
http://gauss.vaniercollege.qc.ca/webwork2/NYBramakko/Magnetic_Field/6/?effectiveUser=0954278&displayMode=images&showOldAnswers=1&user=0954278&key=bIyLRnos5NmBC26Vl4DpQdlatGJalrsW
i know how to get the magnetic field due to the semi circle, but for the two finite wires, i know from the integral we get uo I/ 4piR (sin phi1 + sinphi2). But for me when i look at each section of wire, I see the angles going from 0 to 90 degrees, so phi one is 0 degrees and phi 2 is 90 degree. Doing that gives 0. But that is obviously not right. Why do we use 45 degrees i just don't understand it? Please anyone!
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