Magnetic Field due to Power Lines

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SUMMARY

The discussion focuses on estimating the magnetic field produced by overhead power lines operating at 12 kV and delivering a maximum of 47 MW. The calculations involve determining the peak current (I₀) using the formula I₀ = P_max / V₀, resulting in a value of approximately 2769.6 A. The magnetic field (B) is calculated using the equation B = (μ₀I₀) / (2πr), where r is the distance from the wire, set at 25 m. The final magnetic field strength is compared to the Earth's magnetic field strength of 5.0 x 10-5 T.

PREREQUISITES
  • Understanding of AC circuit principles, specifically rms values.
  • Familiarity with magnetic field calculations around current-carrying wires.
  • Knowledge of the permeability of free space (μ₀) and its application in magnetic field equations.
  • Basic algebra for manipulating equations and solving for unknowns.
NEXT STEPS
  • Study the derivation and application of the magnetic field equation B = (μ₀I₀) / (2πr).
  • Learn about the effects of distance on magnetic field strength from power lines.
  • Research the differences between rms and peak values in AC circuits.
  • Explore the implications of electromagnetic fields on human health and safety standards.
USEFUL FOR

Students in physics or electrical engineering, electrical safety professionals, and anyone interested in understanding the impact of overhead power lines on magnetic fields.

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Homework Statement



You want to get an idea of the magnitude of magnetic fields produced by overhead power lines. You estimate that a transmission wire is about 25 m above the ground. The local power company tells you that the line operates a 12 kV and provide a maximum of 47 MW to the local area. Estimate the maximum magnetic field you might experience walking under such a power line, and compare to the Earth's field. [For an ac current, values are rms, and the magnetic field will be changing. Let the Earth's magnetic field strength be 5.0 10-5 T.]


Homework Equations



<br /> \\B = \frac{\mu_{0}I_{0}} {2 \Pi r}<br />
<br /> \\P_{max} = V_{0}I_{0}<br />
<br /> \\V_{0} = \sqrt{2}V_{rms}<br />

The Attempt at a Solution



<br /> \\V_{0} = 12000\sqrt{2} = 16970 V \\<br />
<br /> \\I_{0} = \frac{P_{max}}{V_{0}}= \frac{(47 * 10^6)}{16970} = 2769.6 A \\<br />

Then, the current value is plugged into the equation of a magnetic field due to a wire with r equal to 25 m. All of this seems correct, but I continue to get the problem wrong. Does anyone see where I am tripping up here?

P.S. The very first equation is supposed to be divided by 2PIr, but I cannot get latex to show this for whatever reason...
 
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I don't think they mean that P_max is the power delivered during the maximum voltage of an AC cycle. P_max is the rms power delivered during maximum load.

So P_{max} = 47 MW = V_{rms} * I_{rms}

Then I_0 = \sqrt {2} I_{rms}
 
Ahhhhh, okay. Yea, that fixed it. Thanks a lot!
 

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