Magnetic Field in an Infinitely Long Copper Rod

[Xnipes]

Homework Statement

A long, solid, copper rod has a circular cross-section of diameter 10.0 cm. The rod has a current of 5.0 A, uniformly distributed across its cross-section. Calculate the magnetic field strength at:

a) the centre of the rod
b) 2.5 cm from the centre
c) 5.0 cm from the centre
d) 7.5 cm from the centre

Homework Equations

This is supposed to be done somehow using B = μ/2∏ * I/r

I don't have any calculus knowledge.

The Attempt at a Solution

I've tried many ways, but nothing has been consistent. I assume that I need to figure out the value of I at each different point of the copper rod, which I've tried doing through all this finicky work with area and all this stuff, but I truly don't understand what I'm doing.

 

[danielakkerma]

Hey,
You stated that,

I don't have any calculus knowledge.

.
That's going to be very problematic, and a damper on your solving equations here;
You'll have to consider http://en.wikipedia.org/wiki/Ampere%27s_Law#Integral_form.
Also, remember that you're told that the current is distributed evenly across the cross section, or surface area, in other words, I' = (I/A)*A'(r), where A' is the local area, or, to be precise,
(I/R^2)*r^2, r<=R, where r is the distance from the center, and R=D/2;
So you ought to get, B*2*Pi*r=mu_0*(I/R^2)*r^2.
Master calculus, it's imperative,
Good luck,
Daniel