Magnetic Field of a point charge

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SUMMARY

The discussion focuses on calculating the magnetic field generated by a point charge of -2.9 μC moving along the z-axis at a velocity of +7.3 x 105 m/s. The magnetic field at various positions (r1 to r5) is derived using the formula B = [μ0/4π] * [qv x sin Θ / r2]. Key insights include the necessity to reverse the direction of the magnetic field due to the negative charge and the fact that the magnetic field along the same axis as the charge's velocity is zero Teslas. The calculations for specific positions revealed discrepancies, particularly for r1, where the expected magnetic field was not achieved.

PREREQUISITES
  • Understanding of the Biot-Savart Law for magnetic fields
  • Familiarity with vector cross products
  • Knowledge of the right-hand rule (RHR) for determining magnetic field direction
  • Basic principles of electromagnetism, specifically regarding point charges
NEXT STEPS
  • Review the Biot-Savart Law and its applications in calculating magnetic fields
  • Practice vector cross product calculations in electromagnetism contexts
  • Explore the effects of charge polarity on magnetic field direction using the right-hand rule
  • Investigate common errors in magnetic field calculations involving point charges
USEFUL FOR

Students and educators in physics, particularly those studying electromagnetism, as well as anyone involved in solving problems related to magnetic fields generated by moving charges.

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Homework Statement


A point charge q = -2.9 μC moves along the z-axis with a velocity v = (+7.3 x 105 m/s) k . At the moment it passes the origin, what are the strength and direction of the magnetic field at the following positions? Express each field vector in Cartesian form.

(a) At position r1 = (2.0 cm, 0 cm, 0 cm)
(b) At position r2 = (0 cm, 4.0 cm, 0 cm).
(c) At position r3 = (0 cm, 0 cm 1.5 cm).
(d) At position r4 = (3.5 cm, 1.5 cm, 0 cm).
(e) At position r5 = (3.0 cm, 0 cm, 1.0 cm)

Homework Equations


Bpoint charge = [μ0/4pi] * [qv x sin Θ / r2]

The Attempt at a Solution



I saw that this problem has a negative charge, so I'd have to use the RHR and reverse direction to account for the charge being negative. I also got the fact that the magnetic field at a point along the same axis as the charge's velocity is 0 Teslas.

I ended up with
(a) 0 i + _ j + 0 k
(b) _ i + 0 j + 0 k
(c) 0 i + 0 j + 0 k
(d) _ i + _ j + 0 k
(e) 0 i + _ j + 0 k

However, everytime I used the point charge formula I have, I end up with an incorrect answer. For example, in part (a), with a r = 2 cm = 0.02 m, I plugged that into [μ0/4pi] * [|q|v x sin Θ / r2], and then reversing the sign to account for a negative charge, but it didn't work.
i.e. I calculated that for part (a), a value of 2 cm for r would have a magnetic field of -5.29e-4 T in the j direction, but that's apparently not right.
 
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I calculated that for part (a), a value of 2 cm for r would have a magnetic field of -5.29e-4 T in the j direction, but that's apparently not right.
What makes you think that is not right?

$$\vec B = \frac{\mu_0}{4\pi}\frac{q\vec v\times \vec r}{r^3}$$

For part a: ##\vec v = (0,0,v)^t,\;\vec r = (x,0,0)^t##
$$\vec B = \frac{\mu_0q}{4\pi x^3}\left|\begin{matrix}\hat\imath & \hat\jmath & \hat k\\ 0 & 0 & v\\ x & 0 & 0\end{matrix}\right| = \frac{\mu_0 qv}{4\pi x^2}\hat\jmath$$... plug the numbers in and show me your working.

ref: http://maxwell.ucdavis.edu/~electro/magnetic_field/pointcharge.html
 

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