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Magnetic field of a proton in circular orbit

  1. Feb 21, 2010 #1
    Protons having momentum 7.63*10^-16 kg*m/s are held in a circular orbit of radius 1 km by an upward magnetic field. What is the magnitude of the field? Answer in units of T (Tesla).


    r=mv/qB; where r is the radius of the circular orbit, m is the mass of the particle, v is the velocity of the particle, q is the charge of the particle, and B is the magnitude of the magnetic field

    1000m=(7.63*10^-16 kg*m/s)/(1.6*10^-19 C)(B)
    B=.209 T (wrong)
     
  2. jcsd
  3. Feb 22, 2010 #2
    Hi mjau

    Something's wrong with your calculation.Check it again
     
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