1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Magnetic field of a proton in circular orbit

  1. Feb 21, 2010 #1
    Protons having momentum 7.63*10^-16 kg*m/s are held in a circular orbit of radius 1 km by an upward magnetic field. What is the magnitude of the field? Answer in units of T (Tesla).

    r=mv/qB; where r is the radius of the circular orbit, m is the mass of the particle, v is the velocity of the particle, q is the charge of the particle, and B is the magnitude of the magnetic field

    1000m=(7.63*10^-16 kg*m/s)/(1.6*10^-19 C)(B)
    B=.209 T (wrong)
  2. jcsd
  3. Feb 22, 2010 #2
    Hi mjau

    Something's wrong with your calculation.Check it again
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Similar Discussions: Magnetic field of a proton in circular orbit