Magnetic field of a proton in circular orbit

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SUMMARY

The discussion centers on calculating the magnetic field required to maintain a proton in a circular orbit with a radius of 1 km and a momentum of 7.63 x 10^-16 kg*m/s. The formula used is r = mv/qB, where r is the radius, m is the mass of the proton, v is its velocity, q is the charge, and B is the magnetic field strength. The initial calculation yielded a magnetic field strength of 0.209 T, which was identified as incorrect, prompting a request for recalculation.

PREREQUISITES
  • Understanding of classical mechanics, specifically circular motion
  • Familiarity with electromagnetic theory, particularly the Lorentz force
  • Knowledge of the properties of protons, including mass and charge
  • Proficiency in algebraic manipulation of equations
NEXT STEPS
  • Review the derivation of the formula r = mv/qB in the context of circular motion
  • Calculate the velocity of a proton given its momentum and mass
  • Investigate the effects of varying magnetic field strengths on particle motion
  • Explore applications of magnetic fields in particle accelerators
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Physics students, educators, and professionals in fields related to electromagnetism and particle physics will benefit from this discussion.

mjau001
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Protons having momentum 7.63*10^-16 kg*m/s are held in a circular orbit of radius 1 km by an upward magnetic field. What is the magnitude of the field? Answer in units of T (Tesla).


r=mv/qB; where r is the radius of the circular orbit, m is the mass of the particle, v is the velocity of the particle, q is the charge of the particle, and B is the magnitude of the magnetic field

1000m=(7.63*10^-16 kg*m/s)/(1.6*10^-19 C)(B)
B=.209 T (wrong)
 
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Hi mjau

Something's wrong with your calculation.Check it again
 

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