Magnetic Field Strength Calculation for a Solenoid with Given Parameters

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SUMMARY

The magnetic field strength inside a solenoid can be calculated using the formula B = (μ₀)(n)(I₀). In this discussion, a solenoid with a length of 10 cm, 241 turns, and a radius of 3.00 cm carries a current of 200 mA. The permeability constant μ₀ is given as 1.257 x 10^-6 T·m/A, while the turns density n is calculated as 2410 N/L. The calculated magnetic field strength is B = 6.06E-4 T, but there is confusion regarding the use of μ₀ = 4π(10^-7) T·m/A, which is a more common representation of the permeability of free space.

PREREQUISITES
  • Understanding of solenoid physics and magnetic fields
  • Familiarity with the formula B = (μ₀)(n)(I₀)
  • Knowledge of unit conversions (e.g., mA to A)
  • Basic algebra for solving equations
NEXT STEPS
  • Research the implications of using different values for μ₀ in magnetic field calculations
  • Explore the concept of turns density (n) in solenoids and its impact on magnetic field strength
  • Learn about the applications of solenoids in electromagnetic devices
  • Study the effects of solenoid dimensions on magnetic field strength
USEFUL FOR

Physics students, electrical engineers, and anyone involved in the study or application of electromagnetism and solenoid design.

sphys4
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Homework Statement


A 10 cm long solenoid with 241 turns and radius R = 3.00 cm has a current flowing through it of Io = 200 mA. What is the magnetic field strength inside the solenoid (in T)?

The Attempt at a Solution


So i know i have to use the formula B = (uo)(n)(Io)

uo = a constant 1.257 x 10^-6
n = 241/.1 = 2410 N/L
Io = 200 mA or .2 A

So when plugging in B = (1.257x10^-6)(2410)(.2) = 6.06E-4
I am getting the wrong answer... can someone please tell me where i went wrong?
 
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I think it is correct. Are you sure you don't need to use μ0=4π(10-7)? Even though your answer would just change by a small number.
 

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