Magnetic field strength that emits waves

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Homework Help Overview

The discussion revolves around the relationship between the frequency of electromagnetic waves emitted by electrons in a magnetron and the magnetic field strength required for their motion. The original poster seeks to understand the implications of the emitted wave frequency on the magnetic field strength calculation.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to connect the frequency of the emitted electromagnetic waves with the calculation of the magnetic field strength, questioning whether the emission of waves at the same frequency influences the magnetic field value. Other participants clarify that the frequency relates to the electrons' motion and does not affect the magnetic field strength directly.

Discussion Status

Participants are exploring the relationship between the motion of electrons and the electromagnetic waves they emit. Some guidance has been provided regarding the nature of the forces involved, but there is no explicit consensus on the implications of the wave emission on the magnetic field strength.

Contextual Notes

There is a focus on the assumptions regarding the role of emitted electromagnetic waves and their frequency in the context of magnetic field calculations. The discussion also touches on the nature of electromagnetic radiation and energy transport.

jayayo
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Homework Statement


The microwaves in a microwave oven are produced in a special tube called a magnetron. The electrons orbit the magnetic field at 2.99GHz, and as they do so they emit 2.99GHz electromagnetic waves. What is the magnetic field strength?

Homework Equations


ƒ=qβ/(2Pi*m)
Thus, B= f*2Pi*m/q

The Attempt at a Solution


I got the question right. It's just I am having a bit difficult grasping why. I thought that because they stated that the electrons also emit 2.99Hz electromagnetic waves, that this would influence the answer. Could someone please explain to me if electrons emitting waves of the same frequency has any influence on this question and the found B value? And also, if not, why?

Thank you so much!
 
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The electrons ARE what generate the e-m waves. The frequency is just the electrons' rotational frequency. So I don't know what you mean by ".. the electrons ALSO emit 2.99 GHz electromagnetic waves ...".

The problem just involves equating the Lorentz force with centripetal force which your formula does.
 
rude man said:
The electrons ARE what generate the e-m waves. The frequency is just the electrons' rotational frequency. So I don't know what you mean by ".. the electrons ALSO emit 2.99 GHz electromagnetic waves ...".

The problem just involves equating the Lorentz force with centripetal force which your formula does.

Hi~
Sorry- pretty stupid of me. I just thought because they purposely added the fact that the electrons also emitted EM waves of the same frequency, maybe this would increase or decrease the value of the magnetic field.
What would change due to the fact that the electrons were emitting EM waves of the same frequency? Energy, right? Anything else?
 
jayayo said:
Hi~
Sorry- pretty stupid of me. I just thought because they purposely added the fact that the electrons also emitted EM waves of the same frequency, maybe this would increase or decrease the value of the magnetic field.
What would change due to the fact that the electrons were emitting EM waves of the same frequency? Energy, right? Anything else?

The B field is not affected. Without the electrons there would not be any e-m radiation. If the electrons were present but stationary you would have a static E field on top of the B field but no e-m radiation. Charges have to be accelerated to emit e-m radiation.

E-m radiation carries energy with it. The so-called Poynting vector P indicates the direction of e-m radiation and energy transport. The power flux is P times the area under consideration, expressed as a dot product since both P and area A are vectors, and the units are watts/square meter. So power flow = P*A over any area.

It can be shown that P = E x H.

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