Magnetic Flux Through Wire Loop

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SUMMARY

The discussion focuses on calculating the magnetic flux through a circular wire loop with radius R, positioned a distance d from a long straight wire carrying a current I. The magnetic field B generated by the wire is defined by the equation B = μI/(4π) and is further specified as B(r) = 2I/c*r in cgs units. The flux Φ through the loop is derived using the integral Φ = ∫(d-R)^(d+R) dr (2I/c*r) * 2√(R² - (d-r)²), which combines the magnetic field and the area element. The problem is framed within the context of magnetostatics, referencing Maxwell's equations.

PREREQUISITES
  • Understanding of magnetic fields and their equations, specifically B = μI/(4π)
  • Familiarity with the concept of magnetic flux and the equation Φ = B * A * cos(θ)
  • Knowledge of calculus, particularly integration techniques for area calculations
  • Basic understanding of Maxwell's equations, especially the fourth equation related to magnetostatics
NEXT STEPS
  • Study the derivation and applications of Maxwell's equations in magnetostatics
  • Learn about the Biot-Savart Law and its relation to magnetic fields generated by currents
  • Explore advanced integration techniques for calculating flux in complex geometries
  • Investigate the implications of magnetic flux in electromagnetic theory and applications
USEFUL FOR

Students of electromagnetism, physics educators, and engineers working with magnetic fields and circuits will benefit from this discussion.

bspride
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Homework Statement


A wire loop with radius R is located a distance d from a long straight wire carrying a current I. Find the flux through the loop.

Homework Equations


B = \muI/(4\pi)
Magnetic Field above wire
\phi=B*da*cos\vartheta

The Attempt at a Solution


Somehow you have to combine the two equations to find the flux through the circular loop. Any help would be greatly appreciated as I am stumped.
 
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I don't know whether I have understood rhe problem, but I have worked out the situation in which the wire is on the same plane of the circle (in general I think that the computation is conceptually easy but hard in the practice).

In this case, the magnetic field generated by the wire at distance r is

B(r)=\frac{2I}{cr}

in cgs units.


so, if we assume that d>R>0, we have that the flux \Phi is


\Phi=\int_{d-R}^{d+R}dr\frac{2I}{cr}2\sqrt{R^2-(d-r)^2}
 
Yes you are right that the wire loop is in the same plane as the wire. Care to explain the formula you used for the magnetic field generated by the wire?
 
Yes: from the 4-th Maxwell's equation (ignoring the electric field: the problem is a magnetostatic problem):

\nabla \times \vec{B}=\frac{4\pi}{c}\vec{J}


Integrate over a surface S; transform the integral of the rotor in a line integral through one of the usual theorem (Green's theorem, maybe, but I'm not sure); moreover the integral of J gives the current and you find the relation.
 

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