Magnetic Force direction on a charged particle moving parallel to a wire

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The discussion centers on determining the magnetic force direction on a charged particle moving parallel to a wire. The right-hand rule is used to find the magnetic field direction, which is counterclockwise around the wire when viewed from one end. Participants clarify that the force on the particle is calculated using the vector cross product of velocity and magnetic field, requiring the right-hand rule for that specific calculation. There is some confusion regarding which right-hand rule to apply, with references to Fleming's rule and the standard right-hand rule for cross products. Understanding the magnetic field's orientation relative to the wire's current is crucial for accurately determining the force direction.
Devs

Homework Statement


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Homework Equations


The right hand curl rule gave me the counterclockwise direction for the magnetic field but I am confused about how is it going to work for the particle. Thanks

The Attempt at a Solution

 

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By using the right hand rule for the magnetic field from the wire, you need to determine which direction that the magnetic field ## \vec{B} ## points at the position of the particle. You then need to compute the direction of the force ## \vec{F}=Q( \vec{v} \times \vec{B} ) ## using the right hand rule for the vector cross product.
 
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Charles Link said:
By using the right hand rule for the magnetic field from the wire, you need to determine which direction that the magnetic field ## \vec{B} ## points at the position of the particle. You then need to compute the direction of the force ## \vec{F}=Q( \vec{v} \times \vec{B} ) ## using the right hand rule for the vector cross product.

Thanks for your answer. I tried doing that and I am not able to get the direction at the point at which the particle is. Lastly, which right hand rule do we use to find the force? (Fleming's or the other right hand rule)
 
Devs said:
Thanks for your answer. I tried doing that and I am not able to get the direction at the point at which the particle is. Lastly, which right hand rule do we use to find the force? (Fleming's or the other right hand rule)
For a wire, I always remember the ## B ## field direction as being clockwise (pointing down on the right side) when the current is into the paper=I really don't use a right hand rule for it. You need to translate that when the wire is running along the paper.
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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