- #1
Hardik Batra
- 130
- 5
(1) Magnetic force acting on charge moving in magnetic field is given by,
F = qvBsinθ...F ∝ v
This means that if moving charge particle has more velocity then more magnetic force will act on it.
Due to more magnetic force the direction of velocity changes rapidly and it will move on the circular path of smaller radius.
(2). Now, Radius of circular path , R = mv/qB.
Here, R ∝ v
This equation implies that if velocity of charge particle is more then it will move on a circular path of larger radius.
In the first situation if v is more then it will move on a circular path of smaller radius.
and in the second situation if v is more then it will move on a circular path of larger radius.
There is a contradiction or am i misleading?
Please correct me if i wrong.
F = qvBsinθ...F ∝ v
This means that if moving charge particle has more velocity then more magnetic force will act on it.
Due to more magnetic force the direction of velocity changes rapidly and it will move on the circular path of smaller radius.
(2). Now, Radius of circular path , R = mv/qB.
Here, R ∝ v
This equation implies that if velocity of charge particle is more then it will move on a circular path of larger radius.
In the first situation if v is more then it will move on a circular path of smaller radius.
and in the second situation if v is more then it will move on a circular path of larger radius.
There is a contradiction or am i misleading?
Please correct me if i wrong.