- #1

NP04

- 23

- 1

- Homework Statement
- What determines the size of the image produced by a curved mirror (in terms of magnification)?

- Relevant Equations
- M = -d0/di

+ = upright image = virtual

- = inverted image = real

Magnification

|M|<1 = smaller

|M|>1 = larger

This is my reasoning because the magnification is -d0/di so it is the ratio that matters. Because wouldn't the sign just affect the type of image?? If you consider the sign in image size, you are saying that only one type of image (real/virtual) can be smaller and only one type can be larger.

Please help.

|M|<1 = smaller

|M|>1 = larger

This is my reasoning because the magnification is -d0/di so it is the ratio that matters. Because wouldn't the sign just affect the type of image?? If you consider the sign in image size, you are saying that only one type of image (real/virtual) can be smaller and only one type can be larger.

Please help.