Magnification; What's focal point

Click For Summary
SUMMARY

The discussion centers on the concept of focal points in optical systems, specifically using the equation 1/f = 1/do + 1/di to determine focal length (f). The focal point represents the distance from the lens where parallel light converges to a point, not the image or object height. The magnification (m) is defined as the ratio of image distance (di) to object distance (do), and understanding focal lengths is crucial for designing optical systems to achieve desired magnifications. The focal length is essential for calculating relative distances in optical setups.

PREREQUISITES
  • Understanding of basic optics principles
  • Familiarity with the lens formula (1/f = 1/do + 1/di)
  • Knowledge of magnification concepts (m = hi/ho = -di/do)
  • Experience with optical system design
NEXT STEPS
  • Study the impact of lens curvature on focal length
  • Explore advanced magnification techniques in optical systems
  • Learn about the effects of aberrations on image quality
  • Investigate the use of multiple lens systems for enhanced magnification
USEFUL FOR

Optical engineers, physicists, and students studying optics who seek to deepen their understanding of focal points and magnification in lens systems.

CuteWolf
Messages
4
Reaction score
0
After using the equation 1f = 1÷do + 1÷di I found what the focal point / f was.
Now, what would the focal point represent? Is the focal point the image height or object height in the equation m = hi÷ho = -di÷do
 
Science news on Phys.org
'f' is not a point; 'f' is the focal *distance*. It is the distance from the lens, if plane parallel light were incident on the lens, at which the light would focus to a point.

The magnification of the system is given by the *ratio* of front and back focal lengths (which is equivalent to the ratio of image distance to object distance).

In most optical systems, the focal point (or focal plane) is not a real surface. When designing an optical system, it's often helpful to keep track of the focal planes/lengths, because then it's straightforward to add or modify lenses to get a desired result- a certain magnification, for example.
 
Slight amplification: the focal length of a lens is the distance from the lens where incident light from a point-source "object" at infinity (who's "rays" are effectively parallel) will be focused into a point "image". You can use that length to calculate (with the formula you gave) the relative distances of object and image for any other combination. The magnification is then the ratio of those two distances.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 11 ·
Replies
11
Views
3K