Magnitude and Direction of Normal FOrce

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becsantos
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Homework Statement


A three-tiered birthday cake rests on a table. From bottom to top, the cake tiers weigh 16 N, 9 N, and 5 N, respectively. What is the magnitude and direction of the normal force ating on the second-tier?


Homework Equations


FN=FWcos(theta)


The Attempt at a Solution


5 N = .51 kg
9 N = .92 kg
16 N =1.6 kg
 
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becsantos said:

Homework Statement


A three-tiered birthday cake rests on a table. From bottom to top, the cake tiers weigh 16 N, 9 N, and 5 N, respectively. What is the magnitude and direction of the normal force ating on the second-tier?


Homework Equations


FN=FWcos(theta)
Where did you get this equation? Resist the temptation to memorize equations from other example problems, that will only serve to confuse you. Keep it basic. Everything is in the vertical direction, and nothing is moving, so sum forces in the vertical direction = 0 , when looking at Free Body Diagrams. Please get familiar with them, as they are essential in the study of mechanics. In a Free Body Diagram, you isolate the system , or part of the system, and examine the forces acting on it, both contact forces (like normal forces) and non-contact forces (like gravity), and apply Newton's laws. Give it a try.

The Attempt at a Solution


5 N = .51 kg
9 N = .92 kg
16 N =1.6 kg[/QUOTE]
 
I don't know how to find an answer please help