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jumpingjack90
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Magnitude of Acceleration after initial impulse?
A block with a mass of m = 3.04 kg is at rest on an incline. The angle of the incline is θ = 20.3° with respect to the horizontal. The coefficient of static friction between the object and the incline is μs = 0.645, the coefficient of kinetic friction is μk = 0.449.
a.) What would be the magnitude of the object's acceleration after an initial impulse set it in motion downhill on the incline?
b.)What would be the magnitude of the object's acceleration after an initial impulse set it in motion uphill on the incline?
F=(uk)(mg)(cos(theta))
ma=mgsin(theta)-mg(uk)(cos(theta))
I have no idea what to do. I tried using the above equations and found that
a=(3.04)(9.8)(sin(20.3))-(9.8)(3.04)(cos(20.3))(0.449) / (3.04) = -0.726 m/s^2 which is the wrong answer. ?
Homework Statement
A block with a mass of m = 3.04 kg is at rest on an incline. The angle of the incline is θ = 20.3° with respect to the horizontal. The coefficient of static friction between the object and the incline is μs = 0.645, the coefficient of kinetic friction is μk = 0.449.
a.) What would be the magnitude of the object's acceleration after an initial impulse set it in motion downhill on the incline?
b.)What would be the magnitude of the object's acceleration after an initial impulse set it in motion uphill on the incline?
Homework Equations
F=(uk)(mg)(cos(theta))
ma=mgsin(theta)-mg(uk)(cos(theta))
The Attempt at a Solution
I have no idea what to do. I tried using the above equations and found that
a=(3.04)(9.8)(sin(20.3))-(9.8)(3.04)(cos(20.3))(0.449) / (3.04) = -0.726 m/s^2 which is the wrong answer. ?