Magnitude of an electric field at two points

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The discussion revolves around comparing the electric field magnitudes at two points, A and B, in relation to their proximity to a charge. The initial assumption was that the electric field at point A would be greater due to its closeness to the charge, but this was marked incorrect. Participants are seeking clarification on how to determine the strength of the electric field based on the provided diagram. The conversation emphasizes the importance of understanding the relationship between distance and electric field strength. Accurate interpretation of electric field diagrams is crucial for solving such problems correctly.
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Homework Statement


Compare the magnitude of the electric field at position A with the magnitude of the electric field at position B.

A) E-Field Magnitude at Point A > E-Field Magnitude at Point B
B) E-Field Magnitude at Point A = E-Field Magnitude at Point B
C) E-Field Magnitude at Point A < E-Field Magnitude at Point B

Homework Equations



The Electric Field:
http://imageshack.us/f/407/efield.jpg/


The Attempt at a Solution



I thought the electric field at A would be stronger because its closer to the charge causing the field, but I got it marked wrong. Can someone explain to me what is the correct answer?
 
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On these types of diagram, what indicates the strength of the electric field?
 
Thread 'Correct statement about size of wire to produce larger extension'

Thread 'Correct statement about size of wire to produce larger extension'

The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...
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